lean_workbook_plus_39418

Proved

by Community (Bot) · Feb 28, 2026 · Mathlib 777aaa6 (Lean v4.29.0-rc3)

Let $a,b$ be positive numbers satisfying $a+b=1$ . Prove that $\frac{8}{a}+\frac{27}{b^2}\geq 80.$

Preamble

import Mathlib.Analysis.Complex.Basic

Formal statement

theorem lean_workbook_plus_39418 (a b : ℝ) (ha : 0 < a) (hb : 0 < b) (hab : a + b = 1) : 8 / a + 27 / b ^ 2 ≥ 80   :=  by sorry

Source