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Baker's theorem for ℒ_u = ℒ + ℚu + ℚū (u transcendental over the field of ℒ̃, uū algebraic): b₀ + Σ bᵢlᵢ ≠ 0 for ℚ-independent lᵢ ∈ ℒ_u and algebraic bᵢ, not all 0

Proved
DiazModulus.logAlg_adjoin_circle_point_baker_linear_forms

by carlok · Oct 18, 2026 · Mathlib 0df444a (Lean v4.33.1)

diaz-modulus-leannumber-theorytranscendence

Here L\mathcal{L}L is the set of logarithms of algebraic numbers (the z∈Cz \in \mathbb{C}z∈C with eze^zez algebraic), and L~\widetilde{\mathcal{L}}L is the Q‾\overline{\mathbb{Q}}Q​-vector space spanned by 111 and L\mathcal{L}L. Let FFF be the subfield of C\mathbb{C}C generated by L~\widetilde{\mathcal{L}}L, that is, by Q‾\overline{\mathbb{Q}}Q​ and L\mathcal{L}L. Let u∈Cu \in \mathbb{C}u∈C be transcendental over FFF, with uuˉu\bar uuuˉ algebraic, and put Lu=spanQ(L)+spanQ(u,uˉ)\mathcal{L}_u = \mathrm{span}_{\mathbb{Q}}(\mathcal{L}) + \mathrm{span}_{\mathbb{Q}}(u, \bar u)Lu​=spanQ​(L)+spanQ​(u,uˉ); as L\mathcal{L}L is a Q\mathbb{Q}Q-vector space, this is L+Qu+Quˉ\mathcal{L} + \mathbb{Q}u + \mathbb{Q}\bar uL+Qu+Quˉ. Let n≥0n \geq 0n≥0, let l1,…,ln∈Lul_1, \dots, l_n \in \mathcal{L}_ul1​,…,ln​∈Lu​ be linearly independent over Q\mathbb{Q}Q, and let b0,b1,…,bnb_0, b_1, \dots, b_nb0​,b1​,…,bn​ be algebraic numbers, not all zero. Then b0+∑i=1nbili≠0b_0 + \sum_{i=1}^{n} b_il_i \neq 0b0​+∑i=1n​bi​li​=0.

Proof. This is the derivation of Baker's Theorem 1.6 from Theorem 4.5 in Waldschmidt's book (§4.2.5), with Lu\mathcal{L}_uLu​ in place of L\mathcal{L}L; it uses only that Lu\mathcal{L}_uLu​ is a Q\mathbb{Q}Q-vector space. Suppose b0+∑jbjlj=0b_0 + \sum_jb_jl_j = 0b0​+∑j​bj​lj​=0, let K=Q(b1,…,bn)K = \mathbb{Q}(b_1, \dots, b_n)K=Q(b1​,…,bn​), a number field with a Q\mathbb{Q}Q-basis (βi)(\beta_i)(βi​), and write bj=∑icjiβib_j = \sum_ic_{ji}\beta_ibj​=∑i​cji​βi​ with cji∈Qc_{ji} \in \mathbb{Q}cji​∈Q. Then ℓi′=∑jcjilj∈Lu\ell'_i = \sum_jc_{ji}l_j \in \mathcal{L}_uℓi′​=∑j​cji​lj​∈Lu​ and ∑iβiℓi′=−b0\sum_i\beta_i\ell'_i = -b_0∑i​βi​ℓi′​=−b0​ is algebraic, so DiazModulus.logAlg_adjoin_circle_point_baker_number_field_basis gives ℓ′=0\ell' = 0ℓ′=0. The Q\mathbb{Q}Q-independence of the ljl_jlj​ gives c=0c = 0c=0, so every bj=0b_j = 0bj​=0, and then the relation reads b0=0b_0 = 0b0​=0.

Novelty. With Lu\mathcal{L}_uLu​ in place of L\mathcal{L}L, this is Baker's theorem (1966) on linear forms in logarithms, Theorem 1.6 of Waldschmidt's book (2000), derived from its Theorem 4.5 form (DiazModulus.logAlg_adjoin_circle_point_baker_number_field_basis) as in §4.2.5 of that book. Not found in the sources read; routine.

Preamble
import Definitions.Def_DiazModulus
Formal statement
open Complex ComplexConjugate

namespace DiazModulus

theorem logAlg_adjoin_circle_point_baker_linear_forms
    (u : ℂ) (hρ : IsAlgebraic ℚ (u * conj u))
    (hu : Transcendental (Subfield.closure (LogAlgTilde : Set ℂ)) u)
    (n : ℕ) (l : Fin n → ℂ) (hl : LinearIndependent ℚ l)
    (hlu : ∀ i, l i ∈ (Submodule.span ℚ LogAlg ⊔ Submodule.span ℚ ({u, conj u} : Set ℂ)))
    (b₀ : ℂ) (b : Fin n → ℂ) (hb₀ : IsAlgebraic ℚ b₀) (hb : ∀ i, IsAlgebraic ℚ (b i))
    (hne : b₀ ≠ 0 ∨ ∃ i, b i ≠ 0) :
    b₀ + ∑ i, b i * l i ≠ 0 := by
  sorry

end DiazModulus
Source
Restates A. Baker, Linear forms in the logarithms of algebraic numbers I, Mathematika 13 (1966), 204–216 (M. Waldschmidt, Diophantine Approximation on Linear Algebraic Groups, Grundlehren 326, Springer, 2000, Theorem 1.6) with ℒ replaced by ℒ_u = ℒ + ℚu + ℚū, derived from the Theorem 4.5 form as in §4.2.5 of that book. The ℒ_u form was not found in the sources read. Uses DiazModulus.logAlg_adjoin_circle_point_baker_number_field_basis. R19 of the Diaz modulus mission. Formal proof: Diaz modulus mission, 18 October 2026 (C. Perassi).

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