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Section 3 — printed counterexample and nonradical correction

Proved
PhilipponMultiplicity.section_three_counterexample

by tomasz · Sep 23, 2026 · Mathlib 0df444a (Lean v4.33.1)

draft-statementphilippon-multiplicity

Compiled open theorem statement; proof not yet supplied. Checked locally with Lean 4.33.1 and the proposal’s pinned Mathlib. An independent blind readback is attached.

Keep the exact printed three-generator ideal, its degree four, its two degree-one sections, and the isolated primary components of degrees four and two. Their degree sum is six. Contrary to the printed word “prime”, the original ideal is nonradical: the draft requires an explicit cubic witness and its square membership.

Preamble
/-
The actual p.370–371 example. Correction: the printed three-generator I₀
is not prime and not radical, as witnessed by the explicit cubic below.
Its degree and the displayed two-component section still give 6 > 4.
-/
import Definitions.Def_PhilipponMultiplicity_SectionThreeSupport

set_option autoImplicit false
open scoped BigOperators
Formal statement
namespace PhilipponMultiplicity
open SectionThree SectionThreeSupport

theorem section_three_counterexample :
    let M := BezoutBoundary.ambient
    let I₀ := BezoutBoundary.initialIdeal
    let I := BezoutBoundary.sectionIdeal
    let Q₁ := BezoutBoundary.firstComponent
    let Q₂ := BezoutBoundary.secondComponent
    let g := BezoutBoundary.nonradicalWitness
    IsMultihomogeneousIdeal M I₀ ∧ IsNontrivialIdeal M I₀ ∧
    M.IsHomogeneous BezoutBoundary.firstEquation (fun _ => 1) ∧
    M.IsHomogeneous BezoutBoundary.secondEquation (fun _ => 1) ∧
    g ∉ I₀ ∧ g ^ 2 ∈ I₀ ∧ g ∈ I₀.radical ∧ I₀.radical ≠ I₀ ∧ ¬ I₀.IsPrime ∧
    idealDimension M I₀ = 2 ∧
    Hilbert.hilbertPolynomial ℂ M.factorCount M.ambientDimension I₀ =
      BezoutBoundary.expectedInitialHilbertPolynomial ∧
    idealDegreeValue M I₀ (fun _ => 1) = 4 ∧
    I = BezoutBoundary.reducedSectionGenerators ∧ I = Q₁ ⊓ Q₂ ∧
    Q₁.IsPrimary ∧ Q₂.IsPrimary ∧ Q₁.radical ≠ Q₂.radical ∧
    I.minimalPrimes = {Q₁.radical, Q₂.radical} ∧
    Hilbert.IsRelevant ℂ M.factorCount M.ambientDimension Q₁.radical ∧
    Hilbert.IsRelevant ℂ M.factorCount M.ambientDimension Q₂.radical ∧
    idealDimension M Q₁ = 0 ∧ idealDimension M Q₂ = 0 ∧
    Hilbert.hilbertPolynomial ℂ M.factorCount M.ambientDimension Q₁ = 4 ∧
    Hilbert.hilbertPolynomial ℂ M.factorCount M.ambientDimension Q₂ = 2 ∧
    idealDegreeValue M Q₁ (fun _ => 1) = 4 ∧
    idealDegreeValue M Q₂ (fun _ => 1) = 2 ∧
    componentHilbertSum M I (⊤ : MaximalOpenLocus M) (fun _ => 1) = 6 ∧
    componentHilbertSum M I₀ (⊤ : MaximalOpenLocus M) (fun _ => 1) = 4 ∧
    componentHilbertSum M I₀ (⊤ : MaximalOpenLocus M) (fun _ => 1) <
      componentHilbertSum M I (⊤ : MaximalOpenLocus M) (fun _ => 1) ∧
    ¬ IsLocallyCohenMacaulayOn M I₀ (⊤ : MaximalOpenLocus M) := by sorry

end PhilipponMultiplicity
Source
1986, pp.370–371. https://numdam.org/articles/10.24033/bsmf.2060/
Read-back

What the Lean code literally says, in plain math · gpt-6

Work over C\mathbb CC in the single projective space P4\mathbb P^4P4, with s=1s=1s=1, N0=4N_0=4N0​=4, and R=C[X0,X1,X2,X3,X4]R=\mathbb C[X_0,X_1,X_2,X_3,X_4]R=C[X0​,X1​,X2​,X3​,X4​], ordinary homogeneous degree, and B=(X0,…,X4)B=(X_0,\ldots,X_4)B=(X0​,…,X4​). For every ideal J⊆RJ\subseteq RJ⊆R, let HJ∈Q[t0,…,ts−1]H_J\in\mathbb Q[t_0,\ldots,t_{s-1}]HJ​∈Q[t0​,…,ts−1​] be the chosen polynomial, if one exists, whose value at every coordinatewise sufficiently large d∈Nsd\in\mathbb N^sd∈Ns is the KKK-dimension of the image of the multidegree-ddd homogeneous polynomial space in R/JR/JR/J; set HJ=0H_J=0HJ​=0 if no such polynomial exists. Put δ(J)=deg⁡totHJ\delta(J)=\deg_{\mathrm{tot}}H_Jδ(J)=degtot​HJ​, with δ(J)=0\delta(J)=0δ(J)=0 when HJ=0H_J=0HJ​=0, ΔJ(d)=δ(J)! (HJ)δ(J)(d)\Delta_J(d)=\delta(J)!\,(H_J)_{\delta(J)}(d)ΔJ​(d)=δ(J)!(HJ​)δ(J)​(d), and cJ(α)=[tα]HJ∏iαi!c_J(\alpha)=[t^\alpha]H_J\prod_i\alpha_i!cJ​(α)=[tα]HJ​∏i​αi​! when ∑iαi=δ(J)\sum_i\alpha_i=\delta(J)∑i​αi​=δ(J), with cJ(α)=0c_J(\alpha)=0cJ​(α)=0 otherwise; (HJ)δ(J)(H_J)_{\delta(J)}(HJ​)δ(J)​ is its total-homogeneous component of that degree. Here there is just one Hilbert variable ttt and one degree argument. Define f1=X12X3−X22X0f_1=X_1^2X_3-X_2^2X_0f1​=X12​X3​−X22​X0​, f2=X1X4−X2X3f_2=X_1X_4-X_2X_3f2​=X1​X4​−X2​X3​, f3=X33−X42X0f_3=X_3^3-X_4^2X_0f3​=X33​−X42​X0​, I0=(f1,f2,f3)I_0=(f_1,f_2,f_3)I0​=(f1​,f2​,f3​), I=I0+(X3,X1−X4)I=I_0+(X_3,X_1-X_4)I=I0​+(X3​,X1​−X4​), Q1=(X12,X22,X3,X1−X4)Q_1=(X_1^2,X_2^2,X_3,X_1-X_4)Q1​=(X12​,X22​,X3​,X1​−X4​), Q2=(X0,X12,X3,X1−X4)Q_2=(X_0,X_1^2,X_3,X_1-X_4)Q2​=(X0​,X12​,X3​,X1​−X4​), and w=X1X32−X2X4X0w=X_1X_3^2-X_2X_4X_0w=X1​X32​−X2​X4​X0​. For an ideal JJJ, let Σ(J)\Sigma(J)Σ(J) be the sum of Δ(JRp)∩R(1)\Delta_{(JR_{\mathfrak p})\cap R}(1)Δ(JRp​)∩R​(1) over minimal primes p\mathfrak pp of JJJ with B⊈pB\nsubseteq\mathfrak pB⊈p that are contained in some maximal ideal; this is the component Hilbert sum for the entire maximal spectrum. The assertion says, simultaneously: I0I_0I0​ is stable under all homogeneous-component projections and B⊈I0B\nsubseteq\sqrt{I_0}B⊈I0​​; both X3X_3X3​ and X1−X4X_1-X_4X1​−X4​ are homogeneous of degree one; w∉I0w\notin I_0w∈/I0​, w2∈I0w^2\in I_0w2∈I0​, w∈I0w\in\sqrt{I_0}w∈I0​​, I0≠I0\sqrt{I_0}\ne I_0I0​​=I0​, and I0I_0I0​ is not prime; δ(I0)=2\delta(I_0)=2δ(I0​)=2, HI0=2t2+3t+1H_{I_0}=2t^2+3t+1HI0​​=2t2+3t+1, and ΔI0(1)=4\Delta_{I_0}(1)=4ΔI0​​(1)=4; I=(X12,X22X0,X3,X1−X4)=Q1∩Q2I=(X_1^2,X_2^2X_0,X_3,X_1-X_4)=Q_1\cap Q_2I=(X12​,X22​X0​,X3​,X1​−X4​)=Q1​∩Q2​; Q1,Q2Q_1,Q_2Q1​,Q2​ are primary, have unequal radicals, and Min⁡(I)={Q1,Q2}\operatorname{Min}(I)=\{\sqrt{Q_1},\sqrt{Q_2}\}Min(I)={Q1​​,Q2​​}; both radicals are relevant, meaning neither contains BBB; δ(Q1)=δ(Q2)=0\delta(Q_1)=\delta(Q_2)=0δ(Q1​)=δ(Q2​)=0, HQ1=4H_{Q_1}=4HQ1​​=4, HQ2=2H_{Q_2}=2HQ2​​=2, ΔQ1(1)=4\Delta_{Q_1}(1)=4ΔQ1​​(1)=4, and ΔQ2(1)=2\Delta_{Q_2}(1)=2ΔQ2​​(1)=2; Σ(I)=6\Sigma(I)=6Σ(I)=6, Σ(I0)=4\Sigma(I_0)=4Σ(I0​)=4, and Σ(I0)<Σ(I)\Sigma(I_0)<\Sigma(I)Σ(I0​)<Σ(I); and I0I_0I0​ is not locally Cohen–Macaulay on the entire maximal spectrum. The last negation means it is false that for every maximal ideal m\mathfrak mm the local quotient Rm/I0RmR_{\mathfrak m}/I_0R_{\mathfrak m}Rm​/I0​Rm​ is the zero ring or has a finite regular sequence of nonunits whose length equals its extended-valued Krull dimension. There are no hypotheses or variable choices in this theorem: all rings, polynomials, ideals, dimensions, and degree arguments in the conjunction are the specified concrete ones.

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