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An edge of a relaxation either is an edge of the polytope or exits it at a neighbouring vertex

Proved
Hirsch.relaxation_exit_vertex

by elmismisimoxhunca · Sep 5, 2026 · Mathlib c5ea003 (Lean v4.30.0)

hirsch-conjecturelinear-programmingpolytopes

Let P={x∈Rd:⟨ai,x⟩≤bi, i<n}P=\{x\in\mathbb{R}^d:\langle a_i,x\rangle\le b_i,\ i<n\}P={x∈Rd:⟨ai​,x⟩≤bi​, i<n}, let TTT be a set of row indices, and let Q⊇PQ\supseteq PQ⊇P be a set on which the inequalities indexed by TTT hold. Let x∈Px\in Px∈P and let [x,y][x,y][x,y] be an edge of QQQ (that is, Adj(Q,x,y)\mathrm{Adj}(Q,x,y)Adj(Q,x,y): x≠yx\ne yx=y and the segment [x,y][x,y][x,y] is an extreme subset of QQQ). Then:

  1. if y∈Py\in Py∈P, the segment [x,y][x,y][x,y] is an edge of PPP: Adj(P,x,y)\mathrm{Adj}(P,x,y)Adj(P,x,y);
  2. if y∉Py\notin Py∈/P, there is a point z∈[x,y]z\in[x,y]z∈[x,y] with z=xz=xz=x or Adj(P,x,z)\mathrm{Adj}(P,x,z)Adj(P,x,z), at which some inequality with index outside TTT is tight:
∃ j∉T,⟨aj,z⟩=bj.\exists\, j\notin T,\quad \langle a_j,z\rangle=b_j .∃j∈/T,⟨aj​,z⟩=bj​.

In words: walking from xxx along an edge of the relaxation, one either stays inside PPP along an edge of PPP, or leaves PPP through one of the dropped inequalities, and the exit point is xxx itself or a neighbour of xxx in PPP. This is the geometric content of the Kalai--Kleitman sentence "a shorter path in QQQ could not be a path in PPP and thus must meet a facet not in FvF_vFv​"; no simplicity or general-position hypothesis is used.

Formalization Note The exit point zzz is the last point of [x,y][x,y][x,y] inside PPP; P∩[x,y]P\cap[x,y]P∩[x,y] is an extreme subset of PPP because [x,y][x,y][x,y] is extreme in Q⊇PQ\supseteq PQ⊇P.

Preamble
import Mathlib
import Definitions.Def_Hirsch_model

open scoped RealInnerProductSpace
Formal statement
namespace Hirsch

theorem relaxation_exit_vertex (d n : ℕ)
    (a : Fin n → EuclideanSpace ℝ (Fin d)) (b : Fin n → ℝ)
    (T : Finset (Fin n)) (Q : Set (EuclideanSpace ℝ (Fin d)))
    (hPQ : Hpoly a b ⊆ Q) (hQ : ∀ z ∈ Q, ∀ j ∈ T, ⟪a j, z⟫ ≤ b j)
    (x y : EuclideanSpace ℝ (Fin d)) (hx : x ∈ Hpoly a b) (hadj : Adj Q x y) :
    (y ∈ Hpoly a b → Adj (Hpoly a b) x y) ∧
    (y ∉ Hpoly a b → ∃ z ∈ segment ℝ x y, (z = x ∨ Adj (Hpoly a b) x z) ∧
        ∃ j, j ∉ T ∧ ⟪a j, z⟫ = b j) := by sorry

end Hirsch
Source
G. Kalai, D. J. Kleitman, A quasi-polynomial bound for the diameter of graphs of polyhedra, Bull. AMS 26 (1992) 315-316, proof of the Lemma (the relaxed polyhedron cut out by the touched facets has no shorter paths), https://arxiv.org/abs/math/9204233; M. J. Todd, arXiv:1402.3579, Lemma 1. Prove2Me analogue for the full relaxation: Hirsch.relaxation_no_new_neighbours (ccfa0184-461a-49d1-b15d-1c6668e2d911).

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