lean_workbook_plus_67971
Proved⚠️ Retired — specification defect
The Lean statement below does not encode the problem shown on this page, so its
Provedstatus carries no information about that problem. Do not import this node or use it as a dependency.
Find where , , , the sum of a, b, and c sub n, , , , , , .
Why this node was retired
The posted statement is
theorem lean_workbook_plus_67971 (a b c d : ℕ → ℕ) (h₁ : a = fun n => b (n - 1) + c (n - 2)) (h₂ : b = fun n => a (n - 1)) (h₃ : c = fun n => b (n - 2)) (h₄ : d = fun n => a n + b n + c n) (h₅ : a 1 = 1) (h₆ : b 1 = 1) (h₇ : c 1 = 2) (h₈ : a 2 = 2) (h₉ : b 2 = 1) (h₁₀ : c 2 = 2) : d 20 = 1513 := by sorry
Backward recurrences are imposed at zero and early indices despite incompatible supplied initial data.
A proof of a malformed proposition can be a correct proof of that proposition, so this is not a judgment on the accepted submission — but the Proved status must not be read as settling the problem shown above.
Proposed corrected statement
Impose all three recurrences only at n≥3, retain the stated values at indices 1 and 2, and define d(n)=a(n)+b(n)+c(n). Recompute d(20) from this corrected initial-value system before selecting a numeral.
Diagnosis and correction from the public Prove2Me statement audit (wamlat/prove2me-errors). The correction is natural-language mathematics and is not Lean-verified — it is a specification for a corrected node, not a drop-in replacement. No corrected replacement node exists yet.
import Mathlib.Analysis.Complex.Basic
theorem lean_workbook_plus_67971 (a b c d : ℕ → ℕ) (h₁ : a = fun n => b (n - 1) + c (n - 2)) (h₂ : b = fun n => a (n - 1)) (h₃ : c = fun n => b (n - 2)) (h₄ : d = fun n => a n + b n + c n) (h₅ : a 1 = 1) (h₆ : b 1 = 1) (h₇ : c 1 = 2) (h₈ : a 2 = 2) (h₉ : b 2 = 1) (h₁₀ : c 2 = 2) : d 20 = 1513 := by sorry