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Magnitude bound for every prefix zeta stage

Proved
ThreeSum.BoxStages.stageValue_abs_le

by wurtle · Oct 14, 2026 · Mathlib 0df444a (Lean v4.33.1)

3sumalgorithmsfine-grained-complexitythree-sum-1962word-ram

Let L,c,U∈NL,c,U\in\mathbb NL,c,U∈N and let fff assign an integer to every subset of {0,…,L−1}\{0,\ldots,L-1\}{0,…,L−1}. Assume ∣f(S)∣≤U|f(S)|\le U∣f(S)∣≤U whenever ∣S∣≤c|S|\le c∣S∣≤c. Let ZjfZ_jfZj​f be the partial zeta transform after processing the first jjj coordinates. Then

∀j≤L ∀S with ∣S∣≤c,∣Zjf(S)∣≤2jU.\forall j\le L\ \forall S\text{ with }|S|\le c,\qquad |Z_jf(S)|\le2^jU.∀j≤L ∀S with ∣S∣≤c,∣Zj​f(S)∣≤2jU.

Here Zjf(S)=∑X⊆S∩{0,…,j−1}f((S∖{0,…,j−1})∪X)Z_jf(S)=\sum_{X\subseteq S\cap\{0,\ldots,j-1\}}f((S\setminus\{0,\ldots,j-1\})\cup X)Zj​f(S)=∑X⊆S∩{0,…,j−1}​f((S∖{0,…,j−1})∪X). This bounds the stored prefix-stage values used for sparse boxes directly from the original weights.

Preamble
import Aesop
import Definitions.Def_ThreeSum1962Source_Bundle01
import Definitions.Def_ThreeSum1962Source_Bundle04
import Lean.Elab.Tactic.Omega
import Mathlib.Algebra.BigOperators.Group.Finset.Powerset
import Mathlib.Algebra.BigOperators.Group.Finset.Sigma
import Mathlib.Algebra.BigOperators.Ring.Finset
import Mathlib.Algebra.Order.BigOperators.Group.Finset
import Mathlib.Combinatorics.Colex
import Mathlib.Data.Fin.Embedding
import Mathlib.Data.Finset.Card
import Mathlib.Data.Finset.Max
import Mathlib.Data.Finset.Powerset
import Mathlib.Data.List.Basic
import Mathlib.Data.List.Nodup
import Mathlib.Data.Nat.Choose.Basic
import Mathlib.Tactic.ByContra
import Mathlib.Tactic.Linarith
import Mathlib.Tactic.Push
import Mathlib.Tactic.Ring
import Mathlib.Tactic.SplitIfs
import Theorems.Thm_ThreeSum_Subset_partialZeta_insert


set_option autoImplicit false
set_option relaxedAutoImplicit false
set_option Elab.async false

Formal statement
theorem ThreeSum.BoxStages.stageValue_abs_le : ∀ {L cut U : Nat} (f : Finset.{0} (Fin L) → Int)
  (hf :
    ∀ (S : Finset.{0} (Fin L)),
      @LE.le.{0} Nat instLENat (@Finset.card.{0} (Fin L) S) cut →
        @LE.le.{0} Int Int.instLEInt (@abs.{0} Int instLatticeInt Int.instAddGroup (f S))
          (@Nat.cast.{0} Int instNatCastInt U))
  (j : Nat),
  @LE.le.{0} Nat instLENat j L →
    ∀ (S : Finset.{0} (Fin L)),
      @LE.le.{0} Nat instLENat (@Finset.card.{0} (Fin L) S) cut →
        @LE.le.{0} Int Int.instLEInt
          (@abs.{0} Int instLatticeInt Int.instAddGroup (@ThreeSum.BoxStages.stageValue L f j S))
          (@Nat.cast.{0} Int instNatCastInt
            (@HMul.hMul.{0, 0, 0} Nat Nat Nat (@instHMul.{0} Nat instMulNat)
              (@HPow.hPow.{0, 0, 0} Nat Nat Nat
                (@instHPow.{0, 0} Nat Nat (@NPow.toPow.{0} Nat (@Monoid.toNPow.{0} Nat Nat.instMonoid)))
                (@OfNat.ofNat.{0} Nat (nat_lit 2) (instOfNatNat (nat_lit 2))) j)
              U)) := by
  sorry
Source
https://github.com/c0ldzy17/three-sum-lean/blob/2b639655e07421b9ac743de9090459bab473a7c0/Submission/ThreeSum/BoxStages.lean#L61-L83

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