Negative moments of the chi-square distribution: $\mathbb{E}[\Xi^{-q}] = \Gamma(d/2-q)/(2^q\Gamma(d/2))$ for $0 \le q < d/2$

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Negative moments of the chi-square distribution: $\mathbb{E}[\Xi^{-q}] = \Gamma(d/2-q)/(2^q\Gamma(d/2))$ for $0 \le q < d/2$ · Prove2Me