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For u ∉ Q̄ with uū = ρ algebraic and a ∈ Q̄ non-zero with aā = ρ², the conjugation-stable space Q̄ + Q̄u + Q̄ū + Q̄·u/(u² − a) carries no 2×3 configuration

Proved
DiazModulus.conj_stable_circle_point_extension_no_two_by_three_configuration

by carlok · Oct 6, 2026 · Mathlib 0df444a (Lean v4.33.1)

diaz-modulus-leannumber-theorytranscendence

Let u∈C∖Q‾u \in \mathbb{C} \setminus \overline{\mathbb{Q}}u∈C∖Q​ with ρ=uuˉ\rho = u\bar uρ=uuˉ algebraic, and let a∈Q‾a \in \overline{\mathbb{Q}}a∈Q​, a≠0a \neq 0a=0, with aaˉ=ρ2a\bar a = \rho^2aaˉ=ρ2. Then there are no x1,x2x_1, x_2x1​,x2​, independent over Q‾\overline{\mathbb{Q}}Q​, and y1,y2,y3y_1, y_2, y_3y1​,y2​,y3​, independent over Q‾\overline{\mathbb{Q}}Q​, with all six products xiyjx_iy_jxi​yj​ in Q‾+Q‾u+Q‾uˉ+Q‾ u/(u2−a)\overline{\mathbb{Q}} + \overline{\mathbb{Q}}u + \overline{\mathbb{Q}}\bar u + \overline{\mathbb{Q}}\,u/(u^2 - a)Q​+Q​u+Q​uˉ+Q​u/(u2−a).

Here z=u/(u2−a)z = u/(u^2 - a)z=u/(u2−a) has zˉ=−(ρ/aˉ)z\bar z = -(\rho/\bar a)zzˉ=−(ρ/aˉ)z, so the space is stable under conjugation and a hypothesis z∈L~z \in \widetilde{\mathcal{L}}z∈L adds nothing to it; when aaˉ≠ρ2a\bar a \neq \rho^2aaˉ=ρ2 the five-dimensional H0+Q‾z+Q‾zˉH_0 + \overline{\mathbb{Q}}z + \overline{\mathbb{Q}}\bar zH0​+Q​z+Q​zˉ does carry a configuration (DiazModulus.circle_point_conjugate_pair_extension_carries_two_by_three_configuration). So zˉ\bar zzˉ is what lets the strong six exponentials theorem see u/(u2−a)u/(u^2 - a)u/(u2−a). This is also where the hypotheses of Diaz (2004, Th. 2) and Diaz (2007, Cor. 4(4), Th. 7(1)) fail for this family: (1,U,Uˉ)(1, U, \bar U)(1,U,Uˉ) with U=1/(u2−a)U = 1/(u^2 - a)U=1/(u2−a) is Q‾\overline{\mathbb{Q}}Q​-linearly dependent.

Proof. Put z2=u/(u2−a)2z_2 = u/(u^2 - a)^2z2​=u/(u2−a)2. Since ρ2/aˉ=a\rho^2/\bar a = aρ2/aˉ=a, zˉ2=(ρ/aˉ2) u3/(u2−a)2\bar z_2 = (\rho/\bar a^2)\,u^3/(u^2 - a)^2zˉ2​=(ρ/aˉ2)u3/(u2−a)2, and w=u/(u2−a)=(aˉ2/ρ)zˉ2−az2w = u/(u^2 - a) = (\bar a^2/\rho)\bar z_2 - a z_2w=u/(u2−a)=(aˉ2/ρ)zˉ2​−az2​ lies in W2=H0+Q‾z2+Q‾zˉ2W_2 = H_0 + \overline{\mathbb{Q}}z_2 + \overline{\mathbb{Q}}\bar z_2W2​=H0​+Q​z2​+Q​zˉ2​. Also w∉H0w \notin H_0w∈/H0​: if w=c0+c1u+c2uˉw = c_0 + c_1u + c_2\bar uw=c0​+c1​u+c2​uˉ, multiplying by u(u2−a)u(u^2 - a)u(u2−a) gives a polynomial c1X4+c0X3+(c2ρ−c1a−1)X2−c0aX−c2ρac_1X^4 + c_0X^3 + (c_2\rho - c_1a - 1)X^2 - c_0aX - c_2\rho ac1​X4+c0​X3+(c2​ρ−c1​a−1)X2−c0​aX−c2​ρa vanishing at the transcendental uuu; its coefficients in degrees 444, 000 and 222 give c1=0c_1 = 0c1​=0, c2=0c_2 = 0c2​=0 and −1=0-1 = 0−1=0. So DiazModulus.circle_point_conjugate_pair_configuration_invisible_to_four_dimensional_extensions, for z2z_2z2​, says that H0+Q‾wH_0 + \overline{\mathbb{Q}}wH0​+Q​w carries no configuration.

Novelty. Not found in the sources read; a short consequence of Theorem B (DiazModulus.circle_point_extension_two_by_three_configuration_iff).

Preamble
import Definitions.Def_DiazModulus
Formal statement
open Complex ComplexConjugate

namespace DiazModulus

theorem conj_stable_circle_point_extension_no_two_by_three_configuration (u a : ℂ)
    (hu : u ∉ Qbar) (hρ : IsAlgebraic ℚ (u * conj u)) (ha : a ∈ Qbar) (ha0 : a ≠ 0)
    (haρ : a * conj a = (u * conj u) ^ 2) :
    ¬ ∃ (x : Fin 2 → ℂ) (y : Fin 3 → ℂ), LinearIndependent (↥Qbar) x ∧ LinearIndependent (↥Qbar) y ∧
      ∀ i j, x i * y j ∈ Submodule.span Qbar ({1, u, conj u, u / (u ^ 2 - a)} : Set ℂ) := by
  sorry

end DiazModulus
Source
Not found in the sources read; it marks where the hypotheses of G. Diaz, Utilisation de la conjugaison complexe dans l'étude de la transcendance de valeurs de la fonction exponentielle usuelle, J. Théor. Nombres Bordeaux 16 (2004), 535–553, Th. 2 (p. 538), and of G. Diaz, Produits et quotients de combinaisons linéaires de logarithmes de nombres algébriques : conjectures et résultats partiels, J. Théor. Nombres Bordeaux 19 (2007), 373–391, Cor. 4(4) and Th. 7(1) (pp. 383, 390), fail for this family. By DiazModulus.circle_point_extension_two_by_three_configuration_iff (Theorem B of the Diaz modulus mission). Formal proof: Diaz modulus mission, 6 October 2026 (C. Perassi).

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