For u ∉ Q̄ with uū = ρ algebraic and a ∈ Q̄ non-zero with aā = ρ², the conjugation-stable space Q̄ + Q̄u + Q̄ū + Q̄·u/(u² − a) carries no 2×3 configuration
ProvedDiazModulus.conj_stable_circle_point_extension_no_two_by_three_configurationLet with algebraic, and let , , with . Then there are no , independent over , and , independent over , with all six products in .
Here has , so the space is stable under conjugation and a hypothesis adds nothing to it; when the five-dimensional does carry a configuration (DiazModulus.circle_point_conjugate_pair_extension_carries_two_by_three_configuration). So is what lets the strong six exponentials theorem see . This is also where the hypotheses of Diaz (2004, Th. 2) and Diaz (2007, Cor. 4(4), Th. 7(1)) fail for this family: with is -linearly dependent.
Proof. Put . Since , , and lies in . Also : if , multiplying by gives a polynomial vanishing at the transcendental ; its coefficients in degrees , and give , and . So DiazModulus.circle_point_conjugate_pair_configuration_invisible_to_four_dimensional_extensions, for , says that carries no configuration.
Novelty. Not found in the sources read; a short consequence of Theorem B (DiazModulus.circle_point_extension_two_by_three_configuration_iff).
import Definitions.Def_DiazModulus
open Complex ComplexConjugate
namespace DiazModulus
theorem conj_stable_circle_point_extension_no_two_by_three_configuration (u a : ℂ)
(hu : u ∉ Qbar) (hρ : IsAlgebraic ℚ (u * conj u)) (ha : a ∈ Qbar) (ha0 : a ≠ 0)
(haρ : a * conj a = (u * conj u) ^ 2) :
¬ ∃ (x : Fin 2 → ℂ) (y : Fin 3 → ℂ), LinearIndependent (↥Qbar) x ∧ LinearIndependent (↥Qbar) y ∧
∀ i j, x i * y j ∈ Submodule.span Qbar ({1, u, conj u, u / (u ^ 2 - a)} : Set ℂ) := by
sorry
end DiazModulus