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§1 — an infinite relaxation sequence with 0<λ⩽20 < \lambda \leqslant 20<λ⩽2 is Fejér-monotone

Proved
RelaxationMethod.LowDim.run_isFejerMonotone

by mikedeng1 · Sep 27, 2026 · Mathlib 0df444a (Lean v4.33.1)

fejer-monotonep2o-batch-p100bp2o-gran-per-chapterp2o-plan-paperp2o-v1relaxation-method

Let A=⋂iHiA = \bigcap_i H_iA=⋂i​Hi​ be the solution polytope of a system of linear inequalities, assumed nonempty, and let 0<λ⩽20 < \lambda \leqslant 20<λ⩽2. Let p0,p1,…p_0, p_1, \dotsp0​,p1​,… be an infinite sequence produced by the relaxation process: every pνp_\nupν​ lies outside AAA, and pν+1p_{\nu+1}pν+1​ is obtained from pνp_\nupν​ by a relaxation step with parameter λ\lambdaλ. Then {pν}\{p_\nu\}{pν​} is Fejér-monotone with respect to AAA:

pν≠pν+1,∣pν−a∣⩾∣pν+1−a∣(a∈A, ν=0,1,… ).p_\nu \neq p_{\nu+1}, \qquad |p_\nu - a| \geqslant |p_{\nu+1} - a| \quad (a \in A,\ \nu = 0, 1, \dots).pν​=pν+1​,∣pν​−a∣⩾∣pν+1​−a∣(a∈A, ν=0,1,…).

This observation from §1 is the link between the process and Lemma 1, and is used in the proofs of Theorems 1 and 2.

Formalization Note The paper argues for 0<λ<20 < \lambda < 20<λ<2 (strict inequality for aaa in HjH_jHj​) and notes that for λ=2\lambda = 2λ=2 (1.1) holds with equality allowed; the statement covers the whole range 0<λ⩽20 < \lambda \leqslant 20<λ⩽2 with the non-strict inequality (2.2), as §5 and §8 use it. The run is a sequence ppp with a relaxation step after every point outside AAA, together with the hypothesis that no point lies in AAA.

Preamble
import Mathlib
import Definitions.Def_RelaxationMethod_LowDim_RelaxStep
import Definitions.Def_RelaxationMethod_Shared_FejerMonotone
Formal statement
namespace RelaxationMethod.LowDim

/-- §1, pp. 393–394 (restated in §5, p. 398): an infinite sequence produced by the relaxation
process with `0 < λ ⩽ 2` is Fejér-monotone with respect to the (nonempty) polytope `A`. -/
theorem run_isFejerMonotone {n m : ℕ} (a : Fin m → EuclideanSpace ℝ (Fin n)) (b : Fin m → ℝ)
    (hA : (polytope a b).Nonempty) (lam : ℝ) (hlam0 : 0 < lam) (hlam2 : lam ≤ 2)
    (p : ℕ → EuclideanSpace ℝ (Fin n))
    (hrun : ∀ ν, p ν ∉ polytope a b → IsRelaxStep a b lam (p ν) (p (ν + 1)))
    (hinf : ∀ ν, p ν ∉ polytope a b) :
    RelaxationMethod.Shared.IsFejerMonotone (polytope a b) p := by sorry

end RelaxationMethod.LowDim
Source
Motzkin and Schoenberg, The relaxation method for linear inequalities, Canad. J. Math. 6 (1954), DOI 10.4153/CJM-1954-038-x, pp. 393–394, §1 (restated p. 398, §5)
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What the Lean code literally says, in plain math · claude-opus-5-5

Setting. Work in Rn\mathbb{R}^nRn with the standard inner product.

  • There are mmm vectors a1,…,am∈Rna_1,\dots,a_m\in\mathbb{R}^na1​,…,am​∈Rn and mmm reals b1,…,bmb_1,\dots,b_mb1​,…,bm​.
  • Each iii gives a half-space Hi={x:⟨ai,x⟩+bi≥0}H_i=\{x:\langle a_i,x\rangle+b_i\ge 0\}Hi​={x:⟨ai​,x⟩+bi​≥0}.
  • The polytope is A=⋂iHiA=\bigcap_i H_iA=⋂i​Hi​. It is assumed nonempty.
  • d(p,S)d(p,S)d(p,S) is the distance from a point to a set, with d(p,∅)=0d(p,\emptyset)=0d(p,∅)=0.
  • λ\lambdaλ is a real number with 0<λ≤20<\lambda\le 20<λ≤2.
  • (pν)ν≥0(p_\nu)_{\nu\ge 0}(pν​)ν≥0​ is a sequence in Rn\mathbb{R}^nRn.

Hypotheses on the sequence.

  • pν∉Ap_\nu\notin Apν​∈/A for every ν≥0\nu\ge 0ν≥0.
  • Whenever pν∉Ap_\nu\notin Apν​∈/A (so, by the previous point, for every ν\nuν), pν+1p_{\nu+1}pν+1​ comes from pνp_\nupν​ by a relaxation step with parameter λ\lambdaλ. This means there is an index jjj (it may depend on ν\nuν, with no fixed tie-breaking rule) such that:
    • d(pν,Hi)≤d(pν,Hj)d(p_\nu,H_i)\le d(p_\nu,H_j)d(pν​,Hi​)≤d(pν​,Hj​) for all iii;
    • there is a q∈Hjq\in H_jq∈Hj​ with ∣pν−q∣=d(pν,Hj)|p_\nu-q|=d(p_\nu,H_j)∣pν​−q∣=d(pν​,Hj​) and pν+1=pν+λ(q−pν)p_{\nu+1}=p_\nu+\lambda(q-p_\nu)pν+1​=pν​+λ(q−pν​).

The initial point p0p_0p0​ is arbitrary apart from lying outside AAA.

Claim. The sequence (pν)(p_\nu)(pν​) satisfies the predicate "Fejér-monotone with respect to AAA". This predicate comes from an imported definition, RelaxationMethod.Shared.IsFejerMonotone, whose text is not included in the code provided. What exactly is asserted therefore depends on that definition and cannot be unfolded here.

Degenerate cases:

  • m=0m=0m=0. Then A=RnA=\mathbb{R}^nA=Rn, so the hypothesis pν∉Ap_\nu\notin Apν​∈/A cannot hold and the statement is vacuously true.
  • n=0n=0n=0. A nonempty AAA is the whole one-point space, so again the statement is vacuous.
  • λ=0\lambda=0λ=0 is excluded, and so is λ>2\lambda>2λ>2.
Human review
  • Endorsed by Shuze Chen · Sep 27, 2026

    Confirmed by the moderator at approval.

  • Endorsed by mikedeng1 · Sep 27, 2026

    Confirmed by the mission captain (proposal self-audit).

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