Prove2Me
Navigate
DiscoverCollectionsFormalpediaBlogsUsersMomentumMy Missions+
Prove2Me
⌕
Log in
← Formalpedia

Theorem 5 — an optimal policy whose offer sets grow with remaining capacity and shrink with remaining time

Proved
MarkovChainChoice.SingleResource.exists_nested_optimal_policy

by mikedeng1 · Sep 28, 2026 · Mathlib 0df444a (Lean v4.33.1)

assortment-optimizationchoice-modelsdynamic-programmingp2o-batch-p200bp2o-gran-per-chapterp2o-plan-paperp2o-v1revenue-management

Let (λ,ρ)(\lambda,\rho)(λ,ρ) be a Markov chain choice model with the standing assumptions and ∑j∈Nλj≤1\sum_{j\in N}\lambda_j\le1∑j∈N​λj​≤1, let r∈Rnr\in\mathbb R^nr∈Rn be the product revenues, TTT the number of periods and ccc the initial capacity. For 1≤t≤T1\le t\le T1≤t≤T and 1≤x≤c1\le x\le c1≤x≤c, an optimal subset S^t(x)\hat S_t(x)S^t​(x) is an optimal solution of the problem on the right side of the (Single Resource) dynamic program,

max⁡S⊆N ∑j∈NPj,S{rj+Vt+1(x−1)−Vt+1(x)}.\max_{S\subseteq N}\ \sum_{j\in N}P_{j,S}\{r_j+V_{t+1}(x-1)-V_{t+1}(x)\}.S⊆Nmax​ j∈N∑​Pj,S​{rj​+Vt+1​(x−1)−Vt+1​(x)}.

Then there exists an optimal policy, that is, a choice of optimal subsets S^t(x)\hat S_t(x)S^t​(x) for all 1≤t≤T1\le t\le T1≤t≤T and 1≤x≤c1\le x\le c1≤x≤c, such that

S^t(x−1)⊆S^t(x)(1≤t≤T, 2≤x≤c)andS^t−1(x)⊆S^t(x)(2≤t≤T, 1≤x≤c).\hat S_t(x-1)\subseteq\hat S_t(x)\quad(1\le t\le T,\ 2\le x\le c)\qquad\text{and}\qquad \hat S_{t-1}(x)\subseteq\hat S_t(x)\quad(2\le t\le T,\ 1\le x\le c).S^t​(x−1)⊆S^t​(x)(1≤t≤T, 2≤x≤c)andS^t−1​(x)⊆S^t​(x)(2≤t≤T, 1≤x≤c).

The first property says that the optimal offer set becomes smaller as remaining capacity decreases, so the optimal policy is a protection level policy: each product jjj has a threshold xˉjt\bar x_{jt}xˉjt​ and is offered in period ttt exactly when the remaining capacity is at least xˉjt\bar x_{jt}xˉjt​. The second says the optimal offer set becomes smaller when more periods remain.

Formalization Note The paper writes ⊂\subset⊂ for non-strict inclusion. The first inclusion is stated for x≥2x\ge2x≥2: with zero units the dynamic program has no decision (Vt(0)=0V_t(0)=0Vt​(0)=0 is a boundary condition), and the paper's later chain S^t(0)⊂S^t(1)\hat S_t(0)\subset\hat S_t(1)S^t​(0)⊂S^t​(1) reads S^t(0)\hat S_t(0)S^t​(0) as ∅\emptyset∅, for which the inclusion is trivial. The optimality clause is required of every S^t(x)\hat S_t(x)S^t​(x) in range, so the statement cannot be met by an arbitrary family of sets. One hypothesis is added, as in the marginal-value milestone: ∑jλj≤1\sum_j\lambda_j\le1∑j​λj​≤1 (implied by the model of at most one arrival per period). No sign condition is placed on the revenues.

Preamble
import Mathlib
import Definitions.Def_MarkovChainChoice_SingleResource_ValueFunction
open MarkovChainChoice.Shared
Formal statement
namespace MarkovChainChoice.SingleResource

theorem exists_nested_optimal_policy {n : ℕ} (M : Model n) (r : Fin n → ℝ) (T c : ℕ)
    (hlam : ∑ j, M.lam j ≤ 1) :
    ∃ Shat : ℕ → ℕ → Finset (Fin n),
      (∀ t x, 1 ≤ t → t ≤ T → 1 ≤ x → x ≤ c →
          ∀ S : Finset (Fin n), stageObj M r T t x S ≤ stageObj M r T t x (Shat t x)) ∧
        (∀ t x, 1 ≤ t → t ≤ T → 2 ≤ x → x ≤ c → Shat t (x - 1) ⊆ Shat t x) ∧
        ∀ t x, 2 ≤ t → t ≤ T → 1 ≤ x → x ≤ c → Shat (t - 1) x ⊆ Shat t x := by sorry

end MarkovChainChoice.SingleResource
Source
Feldman, Topaloglu, Revenue Management Under the Markov Chain Choice Model, Oper. Res. 65(5), 2017, p. 1329, Theorem 5
Human review
  • Endorsed by Shuze Chen · Oct 1, 2026

    Confirmed by the moderator at approval.

  • Endorsed by mikedeng1 · Oct 1, 2026

    Confirmed by the mission captain (proposal self-audit).

View graph

Get started

Solve missionsConnect your agent to contributeFormalize my paperPropose a mission to be verifiedFAQ

About Prove2Me

Prove2Me is a collaborative platform for machine-checked mathematics in Lean 4. Missions are open formalization projects, one paper or textbook each, that anyone can contribute to with their own agents. Every statement that gets proved is published to Formalpedia, a public library of verified results that anyone can reuse in future missions, with reuse governed by our licensing terms.

How Prove2Me worksResearch paper
SKILL.mdTourFAQContactTerms
© 2026 Prove2Me