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With money hoarding, a general glut is consistent with every agent's budget

Proved
SaysLaw.hoarding_permits_general_glut

by Lucas · Oct 9, 2026 · Mathlib 0df444a (Lean v4.33.1)

economicsgeneral-equilibriummacroeconomicssays-law

Throughout, ι\iotaι is a finite set of agents and GGG a finite set of goods; p=(pg)g∈Gp=(p_g)_{g\in G}p=(pg​)g∈G​ is a real price vector; si=(si,g)gs_i=(s_{i,g})_gsi​=(si,g​)g​ and di=(di,g)gd_i=(d_{i,g})_gdi​=(di,g​)g​ are real vectors giving the quantities agent iii brings to market (supplies) and plans to buy (demands); ⟨p,x⟩=∑g∈Gpgxg\langle p,x\rangle=\sum_{g\in G}p_g x_g⟨p,x⟩=∑g∈G​pg​xg​ is the market value of a bundle xxx; and zg=∑i∈ι(di,g−si,g)z_g=\sum_{i\in\iota}(d_{i,g}-s_{i,g})zg​=∑i∈ι​(di,g​−si,g​) is the aggregate excess demand for good ggg. Each agent holds money mim_imi​ initially.

Assume there is at least one agent. For any prices ppp, any supplies sss and any initial money balances mmm, there exist demands ddd and planned money balances m′m'm′ such that every agent satisfies the monetary budget constraint ⟨p,di⟩+mi′=⟨p,si⟩+mi\langle p,d_i\rangle+m'_i=\langle p,s_i\rangle+m_i⟨p,di​⟩+mi′​=⟨p,si​⟩+mi​ and yet

zg<0for every good g∈G,z_g<0\quad\text{for every good }g\in G,zg​<0for every good g∈G,

i.e. there is a general glut. Once agents may hold on to the proceeds of sales as money instead of spending them, the budget constraints alone no longer rule out a general glut, which is the Keynesian and Marxian objection to Say's law.

Preamble
import Mathlib
import Definitions.Def_SaysLaw_Model
Formal statement
namespace SaysLaw

theorem hoarding_permits_general_glut {ι G : Type*} [Fintype ι] [Nonempty ι] [Fintype G]
    (p : G → ℝ) (supply : ι → G → ℝ) (m : ι → ℝ) :
    ∃ (demand : ι → G → ℝ) (m' : ι → ℝ),
      MonetaryBudget p supply demand m m' ∧ GeneralGlut (excessDemand supply demand) := by sorry

end SaysLaw
Source
Wikipedia, "Say's law" (PDF export supplied with the request); https://en.wikipedia.org/wiki/Say%27s_law
Read-back

What the Lean code literally says, in plain math · Aristotle (Harmonic) — same agent as the drafter; non-blind

Disclosure — NON-BLIND read-back. This read-back was written by the same agent (Aristotle, by Harmonic) that drafted the Lean statement it describes, with full knowledge of the source article and of the intended meaning. It is not independent, blind testimony and must not be mistaken for one. An independent blind read-back is still recommended before the proposal is submitted.

Let ι\iotaι be a finite type assumed nonempty, GGG an arbitrary finite type (possibly empty), p:G→Rp:G\to\mathbb Rp:G→R arbitrary (no sign condition), s:ι→G→Rs:\iota\to G\to\mathbb Rs:ι→G→R and m:ι→Rm:\iota\to\mathbb Rm:ι→R arbitrary. Then there exist d:ι→G→Rd:\iota\to G\to\mathbb Rd:ι→G→R and m′:ι→Rm':\iota\to\mathbb Rm′:ι→R such that (1) for every iii, ∑gpgdi,g+mi′=∑gpgsi,g+mi\sum_g p_g d_{i,g}+m'_i=\sum_g p_g s_{i,g}+m_i∑g​pg​di,g​+mi′​=∑g​pg​si,g​+mi​, and (2) for every g∈Gg\in Gg∈G, ∑i(di,g−si,g)<0\sum_i(d_{i,g}-s_{i,g})<0∑i​(di,g​−si,g​)<0. No sign or nonnegativity condition is imposed on the witnesses ddd and m′m'm′ (demands may be negative), and none relating m′m'm′ to mmm beyond (1). If GGG is empty, (2) holds vacuously.

Human review
  • Endorsed by Shuze Chen · Oct 10, 2026

    Confirmed by the moderator at approval.

  • Endorsed by Lucas · Oct 10, 2026

    Confirmed by the mission captain (proposal self-audit).

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