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Lemma 4.11 — COPTm≥∑iwiκi=COPT∞C^m_{\mathrm{OPT}} \ge \sum_i w_i\kappa_i = C^\infty_{\mathrm{OPT}}COPTm​≥∑i​wi​κi​=COPT∞​

Proved
AvgCompletionSched.InTree.kappa_lower_bound

by mikedeng1 · Sep 26, 2026 · Mathlib 0df444a (Lean v4.33.1)

lower-boundsp2o-batch-p100ap2o-gran-per-chapterp2o-plan-paperp2o-v1scheduling

Let an in-tree instance without release dates be given, and let κi\kappa_iκi​ be the critical-path length of job iii (Definition 4.1). Then:

  1. for every number mmm of machines, every feasible nonpreemptive mmm-machine schedule NNN satisfies
∑iwiκi≤∑iwiCiN,\sum_i w_i\kappa_i\le \sum_i w_i C^N_i ,i∑​wi​κi​≤i∑​wi​CiN​,

so COPTm≥∑iwiκiC^m_{\mathrm{OPT}}\ge\sum_i w_i\kappa_iCOPTm​≥∑i​wi​κi​; 2. with unboundedly many machines the value ∑iwiκi\sum_i w_i\kappa_i∑i​wi​κi​ is attained: some feasible schedule on nnn machines (as many machines as jobs, which is as good as unboundedly many) has ∑iwiCiN=∑iwiκi\sum_i w_i C^N_i=\sum_i w_i\kappa_i∑i​wi​CiN​=∑i​wi​κi​. Together with part 1 this is the equality ∑iwiκi=COPT∞\sum_i w_i\kappa_i=C^\infty_{\mathrm{OPT}}∑i​wi​κi​=COPT∞​.

Part 1 is the second lower bound used in Theorem 4.17.

Formalization Note The optimum is not formed as an infimum: part 1 is stated against every feasible schedule, and COPT∞C^\infty_{\mathrm{OPT}}COPT∞​ is rendered as "attained on nnn machines" (no schedule on any number of machines does better, by part 1).

Preamble
import Mathlib
import Definitions.Def_AvgCompletionSched_InTree_Model
Formal statement
namespace AvgCompletionSched.InTree

/-- Lemma 4.11 (p. 160): `C^m_opt ≥ ∑_i w_i κ_i = C^∞_opt`. First part: every feasible schedule
on any number `m` of machines has value at least `∑_i w_i κ_i`. Second part (the equality with
`C^∞_opt`): with unboundedly many machines (`n` machines suffice for `n` jobs) the value
`∑_i w_i κ_i` is attained, so together with the first part it is the optimum. -/
theorem kappa_lower_bound {n : ℕ} (I : Instance n) :
    (∀ (m : ℕ) (N : Schedule I m), ∑ i, I.w i * kappa I i ≤ N.wct) ∧
    ∃ N : Schedule I n, N.wct = ∑ i, I.w i * kappa I i := by sorry

end AvgCompletionSched.InTree
Source
Chekuri, Motwani, Natarajan, Stein, Approximation Techniques for Average Completion Time Scheduling, SIAM J. Comput. 31(1), 2001, p. 160, Lemma 4.11
Read-back

What the Lean code literally says, in plain math · claude-opus-5-5

Undefined names. The statement uses four names from the imported module Definitions.Def_AvgCompletionSched_InTree_Model, and their definitions are not shown here:

  • Instance(n)\mathrm{Instance}(n)Instance(n), a type of problem instances indexed by a natural number nnn;
  • Schedule(I,m)\mathrm{Schedule}(I, m)Schedule(I,m), a type of objects built from an instance III and a natural number mmm;
  • κI(i)\kappa_I(i)κI​(i), a quantity attached to each index iii of an instance III;
  • wct(N)\mathrm{wct}(N)wct(N), a numerical value attached to each schedule NNN.

This read-back therefore cannot say what an instance or a schedule is, what makes a schedule feasible, how κ\kappaκ is computed, or what number type the values live in. Everything below holds only as far as those hidden definitions give it meaning.

The names suggest a reading: nnn jobs forming an in-tree, mmm machines, weights wiw_iwi​, and weighted total completion time. The documentation comment also describes the theorem as "Lemma 4.11 (p. 160)", with ∑iwiκi=Copt∞\sum_i w_i\kappa_i = C^\infty_{\mathrm{opt}}∑i​wi​κi​=Copt∞​. Both are suggestions only. The comment is not part of the formal assertion, and the code itself never defines or mentions an optimum CoptmC^m_{\mathrm{opt}}Coptm​ or Copt∞C^\infty_{\mathrm{opt}}Copt∞​.

Setting. Fix:

  • a natural number nnn;
  • an instance III of type Instance(n)\mathrm{Instance}(n)Instance(n).

The instance provides a weight wiw_iwi​ for each index iii, and the sum runs over every index iii of that index type. Judging by the sums, the index type is finite, presumably with nnn elements, but the code does not show this. Write

K(I)  =  ∑iwi κI(i).K(I) \;=\; \sum_{i} w_i \,\kappa_I(i).K(I)=i∑​wi​κI​(i).

Claim. The theorem asserts both of the following.

  1. Lower bound. For every natural number mmm and every schedule NNN of type Schedule(I,m)\mathrm{Schedule}(I, m)Schedule(I,m),
K(I)  ≤  wct(N).K(I) \;\le\; \mathrm{wct}(N).K(I)≤wct(N).

The inequality is non-strict.

  1. Attainment with exactly nnn machines. There exists a schedule NNN of type Schedule(I,n)\mathrm{Schedule}(I, n)Schedule(I,n), where the second parameter is the same nnn that indexes the instance, such that
wct(N)  =  K(I).\mathrm{wct}(N) \;=\; K(I).wct(N)=K(I).

The statement makes no other claim. In particular:

  • It does not say that schedules with fewer than nnn machines can reach K(I)K(I)K(I).
  • It does not say that the schedule in part 2 is unique.
  • It does not name K(I)K(I)K(I) as the minimum of anything. That follows only by combining the two parts: over all schedules of type Schedule(I,n)\mathrm{Schedule}(I, n)Schedule(I,n), the least value of wct\mathrm{wct}wct exists and equals K(I)K(I)K(I).

Degenerate cases.

  • n=0n = 0n=0. If the index type is then empty, K(I)K(I)K(I) is the empty sum 000. Part 1 becomes 0≤wct(N)0 \le \mathrm{wct}(N)0≤wct(N) for every schedule on any number of machines. Part 2 then requires a schedule with 000 machines whose value is exactly 000. Whether such a schedule exists depends on the hidden definition of Schedule\mathrm{Schedule}Schedule. If none exists, the theorem is false for n=0n = 0n=0 rather than vacuous.
  • m=0m = 0m=0 in part 1. The claim covers schedules with zero machines. If Schedule(I,0)\mathrm{Schedule}(I, 0)Schedule(I,0) has no elements (for n≥1n \ge 1n≥1, say), that instance of part 1 is vacuous. If it does have elements, each one must satisfy the bound.
  • Empty schedule types in general. If Schedule(I,m)\mathrm{Schedule}(I, m)Schedule(I,m) is empty for some mmm, part 1 says nothing about that mmm.
  • Other effects of the hidden definitions. Nothing here can be judged from the code shown: whether wiw_iwi​ may be zero or negative, and whether κ\kappaκ or wct\mathrm{wct}wct involve subtraction in N\mathbb{N}N, division, or other operations that return a default value on bad inputs.
Human review
  • Endorsed by Shuze Chen · Sep 27, 2026

    Confirmed by the moderator at approval.

  • Endorsed by mikedeng1 · Sep 27, 2026

    Confirmed by the mission captain (proposal self-audit).

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