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Section 4 — the system (3.2) has at most one solution

Proved
BellmanRouting.PolicySpace.routing_equation_unique

by mikedeng1 · Oct 5, 2026 · Mathlib 0df444a (Lean v4.33.1)

dynamic-programmingp2o-batch-pfp2bp2o-gran-per-chapterp2o-plan-paperp2o-v1shortest-pathuniqueness

Let N=n+1≥2N = n + 1 \ge 2N=n+1≥2 and tij>0t_{ij} > 0tij​>0 for all i≠ji \ne ji=j. If FFF and GGG are real vectors indexed by the cities, both solving (3.2), i.e.

Fi=min⁡j≠i [tij+Fj],Gi=min⁡j≠i [tij+Gj] (i≠N),FN=GN=0,F_i = \min_{j \ne i}\,[t_{ij} + F_j],\quad G_i = \min_{j \ne i}\,[t_{ij} + G_j] \ (i \ne N), \qquad F_N = G_N = 0,Fi​=j=imin​[tij​+Fj​],Gi​=j=imin​[tij​+Gj​] (i=N),FN​=GN​=0,

then F=GF = GF=G.

Together with the existence of the minimal times, this identifies "the solution of (3.2)" with the vector of minimal travel times. Section 7 relies on this identification.

Formalization Note FFF and GGG are arbitrary real vectors: no sign or boundedness is assumed. The paper's hypothesis "tij>0t_{ij} > 0tij​>0 for all i,ji, ji,j" is used only off the diagonal, since the diagonal never enters (3.2).

Preamble
import Mathlib
import Definitions.Def_BellmanRouting_PolicySpace_Routing
Formal statement
namespace BellmanRouting.PolicySpace

theorem routing_equation_unique {n : ℕ} (hn : 1 ≤ n)
    (t : Fin (n + 1) → Fin (n + 1) → ℝ) (ht : ∀ i j, i ≠ j → 0 < t i j)
    (F G : Fin (n + 1) → ℝ) (hF : IsRoutingSolution t F) (hG : IsRoutingSolution t G) :
    F = G := by sorry

end BellmanRouting.PolicySpace
Source
Bellman, On a routing problem, Quart. Appl. Math. 16 (1958), p. 88, Section 4, Eqs. (4.1)–(4.6)
Human review
  • Endorsed by Shuze Chen · Oct 5, 2026

    Confirmed by the moderator at approval.

  • Endorsed by mikedeng1 · Oct 5, 2026

    Confirmed by the mission captain (proposal self-audit).

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