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Lean-Workbook Plus 41954: Trigonometric inequality

Proved
WorkbookRestored.plus_41954

by wamlart · Sep 12, 2026 · Mathlib 777aaa6 (Lean v4.29.0-rc3)

lean-workbookrestored-importssource-checked

Let positive a,b,ca,b,ca,b,c satisfy the strict triangle inequalities, and let A,B,C∈(0,π]A,B,C\in(0,\pi]A,B,C∈(0,π] obey cos⁡A=(b2+c2−a2)/(2bc)\cos A=(b^2+c^2-a^2)/(2bc)cosA=(b2+c2−a2)/(2bc) and the two cyclic cosine laws. Then cos⁡Acos⁡B/(ab)+cos⁡Bcos⁡C/(bc)+cos⁡Acos⁡C/(ac)=sin⁡2A/a2\cos A\cos B/(ab)+\cos B\cos C/(bc)+\cos A\cos C/(ac)=\sin^2A/a^2cosAcosB/(ab)+cosBcosC/(bc)+cosAcosC/(ac)=sin2A/a2.

Source: Lean-Workbook row lean_workbook_plus_41954 (Apache-2.0). The unchanged proposition comes from the original record; its missing mathematical imports and namespaces are restored here.

Preamble
import Mathlib.Analysis.SpecialFunctions.Trigonometric.Basic
open Real
Formal statement
theorem WorkbookRestored.plus_41954 (A B C a b c : ℝ) (ha : a > 0) (hb : b > 0) (hc : c > 0) (hab : a + b > c) (hbc : b + c > a) (hca : a + c > b) (hA: 0 < A ∧ A <= π ∧ cos A = (b^2 + c^2 - a^2)/(2*b*c))  (hB: 0 < B ∧ B <= π ∧ cos B = (a^2 + c^2 - b^2)/(2*a*c)) (hC: 0 < C ∧ C <= π ∧ cos C = (a^2 + b^2 - c^2)/(2*a*b)) : (cos A * cos B)/(a * b) + (cos B * cos C)/(b * c) + (cos A * cos C)/(a * c) = (sin A)^2/(a^2)   :=  by sorry
Source
https://huggingface.co/datasets/internlm/Lean-Workbook/blob/main/lean_workbook.json, row lean_workbook_plus_41954; immutable original Prove2Me node 81efe1ba-7212-4e89-836a-5db5c7a53331

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