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Coverage forces envelope rank r≤k−1r\le k-1r≤k−1 (corollary of (E), Erdős 624)

Proved
Erdos624.minimal_envelope_rank_lt

by Ethan Cheung · Oct 24, 2026 · Mathlib 0df444a (Lean v4.33.1)

combinatoricserdos-problems

Setting: UUU is a finite pool of inputs (to apply this to a sub-pool VVV, take UUU to be the subtype VVV), CCC a set of colours, L:P(U)→P(C)L:\mathcal P(U)\to\mathcal P(C)L:P(U)→P(C) an arbitrary list map (e.g. L(A)={g0(A),g1(A)}L(A)=\{g_0(A),g_1(A)\}L(A)={g0​(A),g1​(A)}), k∈Nk\in\mathbb Nk∈N, and u∈Cu\in Cu∈C with u∉L(∅)u\notin L(\emptyset)u∈/L(∅). A set BBB is a hole if u∉L(A)u\notin L(A)u∈/L(A) for all A⊆BA\subseteq BA⊆B. Hu={A:0<∣A∣≤k, u∈L(A), u∉L(A′) ∀A′⊊A}H_u=\{A: 0<|A|\le k,\ u\in L(A),\ u\notin L(A')\ \forall A'\subsetneq A\}Hu​={A:0<∣A∣≤k, u∈L(A), u∈/L(A′) ∀A′⊊A} (minimal witnesses of size ≤k\le k≤k), Z=spanF2{χA:A∈Hu}≤F2UZ=\mathrm{span}_{\mathbb F_2}\{\chi_A: A\in H_u\}\le\mathbb F_2^UZ=spanF2​​{χA​:A∈Hu​}≤F2U​, Q=F2U/ZQ=\mathbb F_2^U/ZQ=F2U​/Z, qx=ex+Zq_x=e_x+Zqx​=ex​+Z, r=dim⁡Qr=\dim Qr=dimQ, ρ(B)=dim⁡span{qx:x∈B}\rho(B)=\dim\mathrm{span}\{q_x:x\in B\}ρ(B)=dimspan{qx​:x∈B}. All of these are written out inline in the Lean statement (no custom definitions).

Corollary. If every kkk-subset Y⊆UY\subseteq UY⊆U contains some AAA with u∈L(A)u\in L(A)u∈L(A) (coverage of uuu), then r<kr<kr<k, i.e. r≤k−1r\le k-1r≤k−1. (For k=0k=0k=0 the hypotheses are contradictory, since u∉L(∅)u\notin L(\emptyset)u∈/L(∅).)

Context: Erdős Problem 624 asks whether H(n)−log⁡2n→∞H(n)-\log_2 n\to\inftyH(n)−log2​n→∞, where H(n)H(n)H(n) is the least mmm such that some f:P(X)→Xf:\mathcal P(X)\to Xf:P(X)→X with ∣X∣=n|X|=n∣X∣=n satisfies f[P(Y)]=Xf[\mathcal P(Y)]=Xf[P(Y)]=X for all ∣Y∣≥m|Y|\ge m∣Y∣≥m. This is an auxiliary finite statement from Sol's Round 12 Step 17 cross-review / resilience analysis of the two-track (PAIR) case. It does not settle Erdős Problem 624, PAIR or Step 17.

Preamble
import Mathlib
open Finset
Formal statement
namespace Erdos624

theorem minimal_envelope_rank_lt {U : Type*} [Fintype U] [DecidableEq U] {C : Type*} [DecidableEq C]
    (L : Finset U → Finset C) (k : ℕ) (u : C) (hu : u ∉ L ∅)
    (hcov : ∀ Y : Finset U, #Y = k → ∃ A ⊆ Y, u ∈ L A) :
    (Module.finrank (ZMod 2) ((U → ZMod 2) ⧸
      Submodule.span (ZMod 2) {v : U → ZMod 2 | ∃ A : Finset U, 0 < #A ∧ #A ≤ k ∧ u ∈ L A ∧
        (∀ A' ⊂ A, u ∉ L A') ∧ v = fun x => if x ∈ A then 1 else 0})) < k := by sorry

end Erdos624
Source
Erdős Problem 624 (https://www.erdosproblems.com/624); Round 12: Sol's 'Step 17: First-Round Cross-Review' and 'Step 17: resilient relations below the top layer'; derived from GPT 6.1 Sol's analysis, relayed by Ethan Cheung; hand-checked and Lean-verified by Grok Bot for Ethan Cheung (Oct 24 2026). Auxiliary result only; does NOT settle PAIR / Step 17 / #624.

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