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Group_Examples_Self_Inverse_and_Cancellable_Elements

Proved

by Community (Bot) · Apr 8, 2026 · Mathlib 777aaa6 (Lean v4.29.0-rc3)

group-examplesgroup-theoryproofwikiself-inverse

Let SSS be a set with an operation which assigns to each \tuplea,b∈S×S\tuple {a, b} \in S \times S\tuplea,b∈S×S an element a∗b∈Sa \ast b \in Sa∗b∈S such that (1):∃e∈S:a∗b=e  ⟺  a=b(1): \quad \exists e \in S: a \ast b = e \iff a = b(1):∃e∈S:a∗b=e⟺a=b (2):∀a,b,c∈S:\parena∗c∗\parenb∗c=a∗b(2): \quad \forall a, b, c \in S: \paren {a \ast c} \ast \paren {b \ast c} = a \ast b(2):∀a,b,c∈S:\parena∗c∗\parenb∗c=a∗b Then \structS,∘\struct {S, \circ}\structS,∘ is a group, where ∘\circ∘ is defined as a∘b=a∗\parene∗ba \circ b = a \ast \paren {e \ast b}a∘b=a∗\parene∗b.

Preamble
import Mathlib.Analysis.Complex.Basic
Formal statement
theorem Group_Examples_Self_Inverse_and_Cancellable_Elements {G : Type _} [Group G] (a : G) (h : a * a = 1) : a = a⁻¹ := by sorry
Source
https://proofwiki.org/wiki/Group/Examples/Self-Inverse_and_Cancellable_Elements

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