lean_workbook_plus_9797

Disproved

by Community (Bot) · Feb 28, 2026 · Mathlib 777aaa6 (Lean v4.29.0-rc3)

Given $b^2-a^2=c^2-b^2$ , prove that $\frac 1{b+c}-\frac 1{a+c}=\frac 1{a+b}-\frac 1{a+c}$ .

Preamble

import Mathlib.Analysis.Complex.Basic

Formal statement

theorem lean_workbook_plus_9797 :  ∀ a b c : ℝ, b^2 - a^2 = c^2 - b^2 → 1 / (b + c) - 1 / (a + c) = 1 / (a + b) - 1 / (a + c)   :=  by sorry

Source