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Theorem 1 - the de Bruijn-Newman constant satisfies Λ≥0\Lambda \ge 0Λ≥0

Proved
DeBruijnNewman.debruijn_newman_constant_nonneg

by Lucas · Sep 13, 2026 · Mathlib 0df444a (Lean v4.33.1)

analysisnumber-theoryriemann-hypothesis

Theorem 1 of the source: Newman's conjecture. The statement has two parts, asserted together:

  1. Λ≥0\Lambda \ge 0Λ≥0, where Λ\LambdaΛ is the infimum of the set of times ttt for which every zero of HtH_tHt​ is real;
  2. every ttt for which HtH_tHt​ has only real zeros satisfies t≥0t \ge 0t≥0.

The second part is the content: it says that for no negative ttt do all zeros of HtH_tHt​ lie on the real axis. Since by Newman's theorem the set of admissible times is the ray [Λ,∞)[\Lambda,\infty)[Λ,∞), the two parts express the same fact; stating both means the theorem does not rest on any convention for the infimum of a set that might be empty or unbounded below, and in particular cannot be satisfied by a junk value.

Combined with the Riemann hypothesis, which is the assertion Λ≤0\Lambda \le 0Λ≤0, this would give Λ=0\Lambda = 0Λ=0.

Preamble
import Mathlib
import Definitions.Def_DeBruijnNewman_core
Formal statement
namespace DeBruijnNewman

theorem debruijn_newman_constant_nonneg :
    0 ≤ Lambda ∧ ∀ t : ℝ, HasOnlyRealZeros t → 0 ≤ t := by sorry

end DeBruijnNewman
Source
B. Rodgers and T. Tao, "The de Bruijn-Newman constant is non-negative", Forum of Mathematics, Pi 8 (2020), e6, https://doi.org/10.1017/fmp.2020.6, Theorem 1, p. 3
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What the Lean code literally says, in plain math · Aristotle (Harmonic) — same agent as the drafter, non-blind

Not an independent read-back — non-blind, written by the drafting agent. This text was written by the same agent that drafted the Lean statements of this proposal, at the explicit instruction of the proposal owner. It is therefore non-blind: its author already knew what the code was intended to say. A platform read-back is normally written by an independent auditor who is given only the Lean code, precisely so that a mismatch between code and intent becomes visible. That safeguard is absent here. No reviewer should mistake the text below for independent testimony; it carries no evidential weight in the faithfulness audit, and an independent read-back is still owed for this item.

The statement has no hypotheses. It asserts the conjunction of two claims about the objects fixed in this bundle, where Ht(z)=∫0∞etu2Φ(u)cos⁡(zu) duH_t(z) = \int_0^\infty e^{tu^2}\Phi(u)\cos(zu)\,duHt​(z)=∫0∞​etu2Φ(u)cos(zu)du, the set SSS consists of those real ttt such that every complex zero of HtH_tHt​ has imaginary part 000, and Λ:=inf⁡S\Lambda := \inf SΛ:=infS taken with the real-number conventions (inf⁡∅=0\inf \emptyset = 0inf∅=0, and inf⁡S=0\inf S = 0infS=0 if SSS is not bounded below):

0≤Λ;0 \le \Lambda;0≤Λ;
  1. for every real ttt: if every complex zzz with Ht(z)=0H_t(z) = 0Ht​(z)=0 has Im⁡z=0\operatorname{Im} z = 0Imz=0, then 0≤t0 \le t0≤t.

Claim 2 says that no negative time belongs to SSS. Claim 1 is a statement about the infimum of SSS under the stated conventions; on its own it would also be satisfied if SSS were empty or unbounded below, which is why the second claim carries the substantive content. Conversely, claim 2 implies that 000 is a lower bound for SSS, from which claim 1 follows under those same conventions.

Nothing here asserts that SSS is nonempty, that it is an interval, or that HtH_tHt​ is entire, integrable, or nonzero.

Human review
  • Endorsed by Shuze Chen · Sep 13, 2026

  • Endorsed by Lucas · Sep 13, 2026

    Confirmed by the mission captain (proposal self-audit).

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