Major and minor integral bounds imply a positive prime count
ProvedTaoFivePrimes.representationCount_pos_of_arc_boundscircle-methodexponential-sumsnumber-theory
Let E be a measurable subset of the unit circle, and M a positive real number. If the real part of the counting integral over E is at least (17/30)M, while the norm of the complementary integral is at most (8001/1000)(1/25)M, then the actual weighted representation count is at least (18497/75000)M and is strictly positive. This is a conditional assembly theorem: it does not establish either analytic estimate.
Preamble
import Definitions.Def_TaoFivePrimes_FourierRepresentation open MeasureTheory TaoFivePrimes
Formal statement
theorem TaoFivePrimes.representationCount_pos_of_arc_bounds (x H : ℕ) (E : Set (AddCircle (1 : ℝ)))
(hE : MeasurableSet E) (M : ℝ) (hM : 0 < M)
(hMajor : (17 / 30 : ℝ) * M ≤
(∫ α in E, representationIntegrand x H α ∂AddCircle.haarAddCircle).re)
(hMinor : ‖∫ α in Eᶜ, representationIntegrand x H α ∂AddCircle.haarAddCircle‖ ≤
(8001 / 1000 : ℝ) * (1 / 25 : ℝ) * M) :
(18497 / 75000 : ℝ) * M ≤ representationCount x H ∧
0 < representationCount x H := by sorrySource
Tao, https://arxiv.org/abs/1201.6656, Section8 circle-method comparison. The constants express a sufficient variant using a global sieve bound and a smaller minor-arc supremum.