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Proof of Lemma 11, p. 13 — reciprocal-exponential bound

Proved
QuantumLinSys.Fourier.bound_p13

by mikedeng1 · Oct 8, 2026 · Mathlib 0df444a (Lean v4.33.1)

complex-analysisfourier-analysisp2o-batch-pfp2ap2o-gran-per-chapterp2o-plan-paperp2o-v1

For each real x∈[−1,1]x\in[-1,1]x∈[−1,1] with x≠0x\ne0x=0,

∣11−e−ix−1ix∣<1.\left|\frac1{1-e^{-ix}}-\frac1{ix}\right|<1.​1−e−ix1​−ix1​​<1.

The bound controls the error caused by replacing an integral in the yyy variable with a finite geometric sum.

Formalization Note The printed phrase “for all x∈[−1,1]x\in[-1,1]x∈[−1,1]” presupposes the reciprocals are defined. Lean explicitly excludes x=0x=0x=0, where totalized division would give a meaningless instance of the inequality.

Preamble
import Mathlib
import Definitions.Def_QuantumLinSys_Fourier_Setting
Formal statement
namespace QuantumLinSys.Fourier

/-- The inline reciprocal-exponential bound in the proof of Lemma 11, p. 13. -/
theorem bound_p13 (x : ℝ) (hx : x ∈ Set.Icc (-1 : ℝ) 1) (hx0 : x ≠ 0) :
    ‖1 / (1 - Complex.exp (-Complex.I * x)) -
      1 / (Complex.I * x)‖ < 1 := by sorry

end QuantumLinSys.Fourier
Source
Childs, Kothari and Somma, Quantum algorithm for systems of linear equations with exponentially improved dependence on precision, arXiv:1511.02306v2, proof of Lemma 11, p. 13, inline bound beginning 'Since |1/(1−e^{−ix}) − 1/(ix)| < 1'
Human review
  • Endorsed by Shuze Chen · Oct 8, 2026

    Confirmed by the moderator at approval.

  • Endorsed by mikedeng1 · Oct 8, 2026

    Confirmed by the mission captain (proposal self-audit).

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