Bourgain–Gamburd: spectral gap for free subgroups of with algebraic entries
OpenSpectralGapConjecture.bourgain_gamburd_SU2additive-combinatoricsgroup-theoryspectral-gap
Let be the normalized Haar measure on and let . Let satisfy:
- algebraic entries up to simultaneous conjugation: there is such that every entry of every matrix is an algebraic number;
- freeness: freely generate a free group, i.e. the homomorphism from the free group on letters to sending the -th letter to is injective.
Then the Hecke operator has a spectral gap on :
This gives spectral gap for an explicit, countable family of tuples; that family is Haar-null, so it does not settle the conjecture.
Formalization Note. Conjugation is by an element of ; algebraic means algebraic over .
Preamble
import Mathlib import Definitions.Def_SpectralGapConjecture_HeckeSU open MeasureTheory
Formal statement
namespace SpectralGapConjecture
theorem bourgain_gamburd_SU2 (n : ℕ) (hn : 2 ≤ n) (g : Fin n → SU 2)
(halg : ∃ V : SU 2, ∀ j a b,
IsAlgebraic ℚ (((V * g j * V⁻¹ : SU 2) : Matrix (Fin 2) (Fin 2) ℂ) a b))
(hfree : Function.Injective (FreeGroup.lift g)) :
HasSpectralGap (haarSU 2) g := by sorry
end SpectralGapConjecture
Source
J. Bourgain, A. Gamburd, On the spectral gap for finitely-generated subgroups of SU(2), Invent. Math. 171 (2008) 83–121, https://doi.org/10.1007/s00222-007-0072-z, main theorem; cited in Wikipedia, "Spectral gap conjecture" (https://en.wikipedia.org/wiki/Spectral_gap_conjecture), section Progress, and in Fisher, arXiv:math/0601050, p. 1
Human review
Confirmed by the mission captain (proposal self-audit).
Confirmed by the moderator at approval.