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Schwarz's lemma for Cartesian products: vanishing on E₁×⋯×Eₙ makes an entire function small

Proved
Transcendence.cartesian_schwarz

by carlok · Oct 2, 2026 · Mathlib 0df444a (Lean v4.33.1)

diaz-modulus-leannumber-theorytranscendence

Let fff be an entire function of n≥1n \ge 1n≥1 complex variables, and let E1,…,EnE_1, \dots, E_nE1​,…,En​ be sets of S1S_1S1​ points in the closed disc of radius r>0r > 0r>0. Suppose that every derivative of fff of total order less than nS0nS_0nS0​ vanishes at every point of E1×⋯×EnE_1 \times \dots \times E_nE1​×⋯×En​, and that ∣f∣≤M|f| \le M∣f∣≤M on the polydisc of radius R≥5rR \ge 5rR≥5r. Then on the polydisc of radius rrr

∣f∣≤n (2⋅3nrR)S0S1M.|f| \le n\,\Bigl(\frac{2\cdot 3^{n} r}{R}\Bigr)^{S_0S_1} M.∣f∣≤n(R2⋅3nr​)S0​S1​M.

This is Proposition 4.7 of Waldschmidt's book in the form used for Baker's theorem. The book assumes vanishing of the partial derivatives with every exponent below S0S_0S0​, which the hypothesis here implies, and has 18n18^n18n in place of 2⋅3n2\cdot 3^n2⋅3n. Total order is the form the application needs: vanishing with every exponent below S0S_0S0​ is not preserved by the linear change of variables in §4.6 of the book, while vanishing by total order is.

It is one step of the proof of Baker's theorem formalised in this mission, which follows Chapter 4 of Waldschmidt's book: Baker's theorem from the criterion of Schneider–Lang for Cartesian products, as observed by Bertrand and Masser (1980).

Proof. One variable at a time: a one-dimensional Hermite division with explicit bounds (the book's step 2.4) and a telescoping over the coordinates, so only one-variable complex analysis is used.

Novelty. None for the statement (the book's Proposition 4.7, with a better constant). The contribution of this node is the formal proof.

Preamble
import Mathlib
Formal statement
namespace Transcendence

/-- **Schwarz's lemma for Cartesian products** (Waldschmidt, *Diophantine Approximation on Linear Algebraic
Groups*, Prop. 4.7, in the form used for Baker's theorem). Let `f` be an entire function of `n ≥ 1` complex
variables, and let `E₁, …, Eₙ` be sets of `S₁` points in the closed disc of radius `r`. If every derivative of
`f` of total order `< n·S₀` vanishes at every point of `E₁ × ⋯ × Eₙ`, and `|f| ≤ M` on the polydisc of radius
`R ≥ 5r`, then `|f| ≤ n·(2·3ⁿ·r/R)^(S₀S₁)·M` on the polydisc of radius `r`. (The book assumes vanishing of the
partial derivatives with every exponent `< S₀`, which the hypothesis here implies, and has `18ⁿ` for `2·3ⁿ`.) -/
theorem cartesian_schwarz {n : ℕ} (hn : 0 < n) (f : (Fin n → ℂ) → ℂ) (hf : AnalyticOnNhd ℂ f Set.univ)
    (E : Fin n → Finset ℂ) {S₀ S₁ : ℕ} (hE : ∀ i, (E i).card = S₁)
    {r R M : ℝ} (hr : 0 < r) (hEr : ∀ i, ∀ ζ ∈ E i, ‖ζ‖ ≤ r) (hR : 5 * r ≤ R)
    (hM : ∀ z ∈ Metric.closedBall (0 : Fin n → ℂ) R, ‖f z‖ ≤ M)
    (hvan : ∀ ξ : Fin n → ℂ, (∀ i, ξ i ∈ E i) → ∀ k < n * S₀, iteratedFDeriv ℂ k f ξ = 0) :
    ∀ z ∈ Metric.closedBall (0 : Fin n → ℂ) r,
      ‖f z‖ ≤ n * (2 * 3 ^ n * r / R) ^ (S₀ * S₁) * M := by
  sorry

end Transcendence
Source
M. Waldschmidt, Diophantine Approximation on Linear Algebraic Groups, Grundlehren 326, Springer, 2000, Proposition 4.7 (pp. 122–130), in the form used in §4.6. Formal proof: Diaz modulus mission, 2 October 2026 (C. Perassi).

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