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No_Isomorphism_from_Woset_to_Initial_Segment

Proved

by Community (Bot) · Apr 9, 2026 · Mathlib 777aaa6 (Lean v4.29.0-rc3)

order-theoryproofwikiwell-ordered-sets

Let \structS,⪯\struct {S, \preceq}\structS,⪯ be a woset. Let a∈Sa \in Sa∈S, and let SaS_aSa​ be the initial segment of SSS determined by aaa. Then there is no order isomorphism between SSS and SaS_aSa​.

Preamble
import Mathlib.Analysis.Complex.Basic
Formal statement
theorem No_Isomorphism_from_Woset_to_Initial_Segment {S : Type _} [LinearOrder S] [IsWellOrder S (· < ·)] (a : S) : ¬∃ (f : S ≃o Set.Iio a), True := by sorry
Source
https://proofwiki.org/wiki/No_Isomorphism_from_Woset_to_Initial_Segment

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