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Integral over an annulus in polar coordinates

Proved
FiniteEnergyPlane.setIntegral_annulus_eq_integral_circleMap

by Mazecto · Oct 24, 2026 · Mathlib 0df444a (Lean v4.33.1)

complex-analysismeasure-theorypolar-coordinates

Let FFF be a real Banach space, 0<a≤b0<a\le b0<a≤b, and f:C→Ff:\mathbb{C}\to Ff:C→F continuous on the closed annulus {a≤∣z∣≤b}\{a\le|z|\le b\}{a≤∣z∣≤b}. Then

∫{a≤∣z∣<b}f(z) dz=∫abr∫02πf(reiθ) dθ dr.\int_{\{a\le|z|<b\}}f(z)\,dz=\int_a^b r\int_0^{2\pi}f(re^{i\theta})\,d\theta\,dr .∫{a≤∣z∣<b}​f(z)dz=∫ab​r∫02π​f(reiθ)dθdr.

This is the polar-coordinates formula for an annulus, with fff only assumed continuous on the closed annulus and not on the whole disc.

Formalization Note The region is ball 0 b \ ball 0 a, and re^{iθ} is circleMap 0 r θ. The integrals are Bochner integrals; the radial integral is the interval integral ∫ r in a..b.

Preamble
import Mathlib.MeasureTheory.Integral.CircleIntegral
import Mathlib.MeasureTheory.Integral.IntervalIntegral.FundThmCalculus
import Mathlib.Analysis.SpecialFunctions.Pow.Real
import Mathlib.Analysis.Calculus.ContDiff.Basic
Formal statement
namespace FiniteEnergyPlane

open MeasureTheory Metric Filter Topology Set
open scoped ContDiff ENNReal Real

/-- Integral over an annulus in polar coordinates. Let `0 < a ≤ b` and let `f` be continuous on the
closed annulus `a ≤ |z| ≤ b`. Then
`∫_{a ≤ |z| < b} f = ∫ₐᵇ r ∫₀^{2π} f(r e^{iθ}) dθ dr`. -/
theorem setIntegral_annulus_eq_integral_circleMap {F : Type*} [NormedAddCommGroup F]
    [NormedSpace ℝ F] [CompleteSpace F] {f : ℂ → F} {a b : ℝ} (ha : 0 < a) (hab : a ≤ b)
    (hf : ContinuousOn f (closedBall 0 b \ ball 0 a)) :
    ∫ z in ball 0 b \ ball 0 a, f z = ∫ r in a..b, r • ∫ θ in 0..2 * π, f (circleMap 0 r θ) := by
  sorry

end FiniteEnergyPlane
Source
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