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Lemma 22.3: for H_{i,j} = |C_j|^{−1/2} 𝟙[i ∈ C_j], the columns of H are orthonormal and RatioCut(C₁,…,C_k) = trace(HᵀLH)

Proved
UnderstandingML.ratiocut_trace

by naimengye · Sep 24, 2026 · Mathlib 0df444a (Lean v4.33.1)

graph-laplacianratiocutspectral-clustering

Lemma 22.3. Let C1,…,CkC_1, \dots, C_kC1​,…,Ck​ be a clustering and let H∈Rm×kH \in \mathbb{R}^{m \times k}H∈Rm×k be the matrix such that Hi,j=1∣Cj∣1[i∈Cj]H_{i,j} = \frac1{\sqrt{|C_j|}}\mathbb{1}[i \in C_j]Hi,j​=∣Cj​∣​1​1[i∈Cj​]. Then, the columns of HHH are orthonormal to each other and RatioCut⁡(C1,…,Ck)=trace⁡(H⊤LH)\operatorname{RatioCut}(C_1, \dots, C_k) = \operatorname{trace}(H^\top L H)RatioCut(C1​,…,Ck​)=trace(H⊤LH).

Formally: WWW symmetric, CCC a partition of [m][m][m] into nonempty clusters; orthonormality as H⊤H=IkH^\top H = I_kH⊤H=Ik​.

Preamble
import Definitions.Def_UnderstandingML_Clustering

open MeasureTheory
Formal statement
namespace UnderstandingML

/-- **Lemma 22.3** (p. 316). Let `C₁, …, C_k` be a clustering and let `H ∈ ℝ^{m×k}` be the matrix
with `H_{i,j} = |Cⱼ|^{−1/2} 𝟙[i ∈ Cⱼ]`. Then the columns of `H` are orthonormal to each other and
`RatioCut(C₁, …, C_k) = trace(Hᵀ L H)`. For a symmetric `W` and a partition of `[m]` into
nonempty clusters. -/
theorem ratiocut_trace {m k : ℕ} (W : Matrix (Fin m) (Fin m) ℝ) (hW : W.IsSymm)
    (C : Fin k → Finset (Fin m)) (hC : IsPartition Finset.univ C) (hne : ∀ i, (C i).Nonempty) :
    (clusterIndicator C).transpose * clusterIndicator C = 1 ∧
      ratioCut W C = Matrix.trace ((clusterIndicator C).transpose * laplacian W * clusterIndicator C) := by sorry

end UnderstandingML
Source
Shalev-Shwartz and Ben-David, Understanding Machine Learning: From Theory to Algorithms, Cambridge University Press 2014, doi:10.1017/CBO9781107298019, §22.3.2 p. 316, Lemma 22.3
Human review
  • Endorsed by Shuze Chen · Sep 25, 2026

    Confirmed by the moderator at approval.

  • Endorsed by naimengye · Sep 25, 2026

    Confirmed by the mission captain (proposal self-audit).

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