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The order of aaa modulo a prime ppp divides p−1p-1p−1

Proved
AlfutovaUstinov.problem_4_114

by evgeth · Sep 28, 2026 · Mathlib 0df444a (Lean v4.33.1)

elementary-number-theoryfermat-little-theoremmultiplicative-ordernumber-theory

This is Problem 4.114 of N. B. Alfutova and A. V. Ustinov, Algebra and Number Theory (MCCME, 2002), Chapter 4, §4 “Theorems of Fermat and Euler”.

Let ppp be a prime and let aaa be an integer not divisible by ppp. Let kkk be the least positive integer such that

ak≡1(modp)a^{k}\equiv 1 \pmod pak≡1(modp)

(the multiplicative order of aaa modulo ppp).

Theorem. Under these assumptions,

k∣p−1.k \mid p-1 .k∣p−1.

This is the basic link between Fermat's little theorem and the orders of residues modulo a prime; it is the starting point of the theory of primitive roots.

Formalization Note The minimality of kkk is expressed by IsLeast {j : ℕ | 0 < j ∧ a ^ j ≡ 1 [ZMOD p]} k: the number kkk is a positive exponent with ak≡1(modp)a^k\equiv 1 \pmod pak≡1(modp), and every positive exponent jjj with aj≡1(modp)a^j\equiv1\pmod paj≡1(modp) satisfies k≤jk\le jk≤j.

Preamble
import Mathlib
Formal statement
namespace AlfutovaUstinov

theorem problem_4_114 (p : ℕ) (hp : p.Prime) (a : ℤ) (ha : ¬ (p : ℤ) ∣ a) (k : ℕ)
    (hk : IsLeast {j : ℕ | 0 < j ∧ a ^ j ≡ 1 [ZMOD p]} k) : k ∣ p - 1 := by sorry

end AlfutovaUstinov
Source
N. B. Alfutova, A. V. Ustinov, «Алгебра и теория чисел. Сборник задач для математических школ» (Algebra and Number Theory: a problem book for mathematical schools), Moscow: MCCME, 2002, Chapter 4 «Арифметика остатков» (Arithmetic of residues), §4 «Теоремы Ферма и Эйлера» (Theorems of Fermat and Euler), Problem 4.114. Problem text and answer as catalogued on problems.ru, problem 60740: https://problems.ru/view_problem_details_new.php?id=60740

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