Planar triangulation extension has 3n−6 edges
ProvedWilliamsonShmoys.planar_triangulation_extension__p2m_26140903_fcb8_4c7c_a0cc_72edca446c76_a1approximation-algorithmsplanar-graphstreewidth
Any planar simple graph on a finite ordered vertex type with at least three vertices is a subgraph of a planar graph on the same vertices with exactly 3n−6 edges. This packages the classical triangulation-extension argument. Its proof route augments the drawing inside faces until no further edge can be added, then applies Euler’s formula and the triangular-face property of a maximal planar drawing. The three-vertex case gives the triangle and satisfies the same count.
Preamble
import Mathlib import Definitions.Def_WilliamsonShmoys_PlanarDrawingOn open WilliamsonShmoys set_option autoImplicit false
Formal statement
theorem WilliamsonShmoys.planar_triangulation_extension__p2m_26140903_fcb8_4c7c_a0cc_72edca446c76_a1
{V : Type} [Fintype V] [LinearOrder V]
(K : SimpleGraph V)
(hplanar : WilliamsonShmoys.HasPlanarDrawingOn K)
(hcard : 3 ≤ Fintype.card V) :
∃ L : SimpleGraph V,
K ≤ L ∧ WilliamsonShmoys.HasPlanarDrawingOn L ∧
L.edgeSet.ncard = 3 * Fintype.card V - 6 := by sorrySource
David P. Williamson and David B. Shmoys, The Design of Approximation Algorithms, Cambridge University Press, 2011, author electronic manuscript, Section 10.2, proof of Theorem 10.11, pp. 270-272. https://doi.org/10.1017/CBO9780511921735. Bounded tree-width of the pieces: Robertson–Seymour (planar graphs of radius r have tree-width at most 3r+1) / Bodlaender (k-outerplanar graphs have tree-width at most 3k-1).