At a candidate u, with Roy's strong six exponentials theorem as hypothesis: for |λ| = 1 algebraic and real f with 1, u, ū, f, f/(|u| + λu) free, f and f/(|u| + λu) are not both in ℒ̃
ProvedDiazModulus.candidate_real_pencil_not_both_mem_logAlgTildeHere is the set of logarithms of algebraic numbers, and is the -vector space spanned by and . Roy's strong six exponentials theorem is carried as the hypothesis hSSE: if are -linearly independent and so are , then one of the six products is not in .
Let be a candidate for Diaz's conjecture (DiazModulus.IsCandidate), with , and real with free over . Then and are not both in . It concerns candidates, so it is vacuous if Diaz's conjecture holds.
Proof. At a candidate (DiazModulus.hermite_lindemann_holds), is algebraic and real with , and (DiazModulus.logAlg_conj_stable). If and are in , then so is , and the configuration of DiazModulus.conj_stable_real_pencil_space_carries_two_by_three_configuration contradicts hSSE.
Novelty. Not asserted: it is one substitution in Diaz (2007, Th. 7(1)), with v₀ = f/(|u| + λu); Diaz (2004, Th. 2) at x = (v₀, v̄₀) also gives it.
import Definitions.Def_DiazModulus
open Complex ComplexConjugate
namespace DiazModulus
theorem candidate_real_pencil_not_both_mem_logAlgTilde
(hSSE : ∀ (x : Fin 2 → ℂ) (y : Fin 3 → ℂ),
LinearIndependent (↥Qbar) x → LinearIndependent (↥Qbar) y →
¬ (∀ i j, x i * y j ∈ LogAlgTilde))
{u : ℂ} (h : IsCandidate u) (lam : ℂ) (hlam : lam ∈ Qbar) (hlam1 : lam * conj lam = 1) (f : ℂ) (hf : conj f = f)
(hind : LinearIndependent (↥Qbar) ![1, u, conj u, f, f / (((‖u‖ : ℝ) : ℂ) + lam * u)]) :
¬ (f ∈ LogAlgTilde ∧ f / (((‖u‖ : ℝ) : ℂ) + lam * u) ∈ LogAlgTilde) := by
sorry
end DiazModulus