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At a candidate u, with Roy's strong six exponentials theorem as hypothesis: for |λ| = 1 algebraic and real f with 1, u, ū, f, f/(|u| + λu) free, f and f/(|u| + λu) are not both in ℒ̃

Proved
DiazModulus.candidate_real_pencil_not_both_mem_logAlgTilde

by carlok · Oct 11, 2026 · Mathlib 0df444a (Lean v4.33.1)

diaz-modulus-leannumber-theorytranscendence

Here L\mathcal{L}L is the set of logarithms of algebraic numbers, and L~\widetilde{\mathcal{L}}L is the Q‾\overline{\mathbb{Q}}Q​-vector space spanned by 111 and L\mathcal{L}L. Roy's strong six exponentials theorem is carried as the hypothesis hSSE: if x1,x2x_1, x_2x1​,x2​ are Q‾\overline{\mathbb{Q}}Q​-linearly independent and so are y1,y2,y3y_1, y_2, y_3y1​,y2​,y3​, then one of the six products xiyjx_iy_jxi​yj​ is not in L~\widetilde{\mathcal{L}}L.

Let uuu be a candidate for Diaz's conjecture (DiazModulus.IsCandidate), λ∈Q‾\lambda \in \overline{\mathbb{Q}}λ∈Q​ with ∣λ∣=1|\lambda| = 1∣λ∣=1, and fff real with 1,u,uˉ,f,f/(∣u∣+λu)1, u, \bar u, f, f/(|u| + \lambda u)1,u,uˉ,f,f/(∣u∣+λu) free over Q‾\overline{\mathbb{Q}}Q​. Then fff and f/(∣u∣+λu)f/(|u| + \lambda u)f/(∣u∣+λu) are not both in L~\widetilde{\mathcal{L}}L. It concerns candidates, so it is vacuous if Diaz's conjecture holds.

Proof. At a candidate u∉Q‾u \notin \overline{\mathbb{Q}}u∈/Q​ (DiazModulus.hermite_lindemann_holds), s=∣u∣s = |u|s=∣u∣ is algebraic and real with s2=uuˉs^2 = u\bar us2=uuˉ, and u,uˉ∈Lu, \bar u \in \mathcal{L}u,uˉ∈L (DiazModulus.logAlg_conj_stable). If fff and ggg are in L~\widetilde{\mathcal{L}}L, then so is WWW, and the configuration of DiazModulus.conj_stable_real_pencil_space_carries_two_by_three_configuration contradicts hSSE.

Novelty. Not asserted: it is one substitution in Diaz (2007, Th. 7(1)), with v₀ = f/(|u| + λu); Diaz (2004, Th. 2) at x = (v₀, v̄₀) also gives it.

Preamble
import Definitions.Def_DiazModulus
Formal statement
open Complex ComplexConjugate

namespace DiazModulus

theorem candidate_real_pencil_not_both_mem_logAlgTilde
    (hSSE : ∀ (x : Fin 2 → ℂ) (y : Fin 3 → ℂ),
      LinearIndependent (↥Qbar) x → LinearIndependent (↥Qbar) y →
      ¬ (∀ i j, x i * y j ∈ LogAlgTilde))
    {u : ℂ} (h : IsCandidate u) (lam : ℂ) (hlam : lam ∈ Qbar) (hlam1 : lam * conj lam = 1) (f : ℂ) (hf : conj f = f)
    (hind : LinearIndependent (↥Qbar) ![1, u, conj u, f, f / (((‖u‖ : ℝ) : ℂ) + lam * u)]) :
    ¬ (f ∈ LogAlgTilde ∧ f / (((‖u‖ : ℝ) : ℂ) + lam * u) ∈ LogAlgTilde) := by
  sorry

end DiazModulus
Source
One substitution in G. Diaz, Produits et quotients de combinaisons linéaires de logarithmes de nombres algébriques : conjectures et résultats partiels, J. Théor. Nombres Bordeaux 19 (2007), 373–391, Th. 7(1) (p. 390); also G. Diaz, Utilisation de la conjugaison complexe dans l'étude de la transcendance de valeurs de la fonction exponentielle usuelle, J. Théor. Nombres Bordeaux 16 (2004), 535–553, Th. 2 (p. 538). Roy's strong six exponentials theorem (D. Roy, Matrices whose coefficients are linear forms in logarithms, J. Number Theory 41 (1992), 22–47, Cor. 2) is carried as a hypothesis. Formal proof: Diaz modulus mission, 11 October 2026 (C. Perassi).

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