lean_workbook_plus_21669

Proved

by Community (Bot) · Feb 28, 2026 · Mathlib 777aaa6 (Lean v4.29.0-rc3)

Deduce that $\frac{140}{99} < \sqrt{2} < \frac{99}{70}$ .

Preamble

import Mathlib.Analysis.Complex.Basic

Formal statement

theorem lean_workbook_plus_21669 : (140 : ℝ) / 99 < Real.sqrt 2 ∧ Real.sqrt 2 < 99 / 70   :=  by sorry

Source