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Integrating a fourth-logarithmic remainder majorant

Proved
TaoFivePrimes.theta_log4_tail_bound

by xuanji · Sep 27, 2026 · Mathlib 0df444a (Lean v4.33.1)

analysisanalytic-number-theoryintegrals

Let x>1x>1x>1 and let EEE be a real-valued function satisfying ∣E(t)∣≤100t/log⁡4t|E(t)|\le100t/\log^4t∣E(t)∣≤100t/log4t for every t≥xt\ge xt≥x. Then

∣∫x∞E(t)log⁡t+1t2log⁡2t dt∣≤25log⁡4x+20log⁡5x.\left|\int_x^\infty E(t)\frac{\log t+1}{t^2\log^2t}\,dt\right|\le\frac{25}{\log^4x}+\frac{20}{\log^5x}.​∫x∞​E(t)t2log2tlogt+1​dt​≤log4x25​+log5x20​.

This calculus comparison converts a pointwise Chebyshev error estimate into the integrated error needed in the reciprocal-prime identity.

Formalization Note The integral is the totalized Bochner integral. Thus no measurability hypothesis on EEE is required: when the integrand is not integrable the integral is zero.

Preamble
import Mathlib
Formal statement
theorem TaoFivePrimes.theta_log4_tail_bound (E : ℝ → ℝ) (x : ℝ)
    (hx : 1 < x)
    (hE : ∀ t : ℝ, x ≤ t → |E t| ≤ 100 * t / (Real.log t) ^ 4) :
    |∫ t in Set.Ioi x, E t * (Real.log t + 1) / (t ^ 2 * (Real.log t) ^ 2)| ≤
      25 / (Real.log x) ^ 4 + 20 / (Real.log x) ^ 5 := by sorry
Source
Elementary integration of the majorant in Vanlalngaia, Explicit Mertens Sums (2017), p. 9, equation (17), https://emis.de/ft/19485: integral of 100(t log(t)^5)^(-1)+100(t log(t)^6)^(-1), using Mathlib MeasureTheory.integral_Ioi_of_hasDerivAt_of_nonneg'.

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