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D4.4c: q-square refinement

Proved
FiniteMagmaE677.period_four_swapped_s_q_square_refinement

by mysticflounder · Sep 24, 2026 · Mathlib 0df444a (Lean v4.33.1)

e677magmaperiod-fourrenewal

Write Lx(y)=x⋄yL_x(y)=x\diamond yLx​(y)=x⋄y and let Cz={Lxi(z):0≤i<dz}C_z=\{L_x^i(z):0\le i<d_z\}Cz​={Lxi​(z):0≤i<dz​} for an exact first-return cycle of length dzd_zdz​. Let a finite magma satisfy E677 and carry the swapped-S one-step packet with p=q⋄(q⋄x)p=q\diamond(q\diamond x)p=q⋄(q⋄x) and u=q⋄pu=q\diamond pu=q⋄p. Put v=q⋄qv=q\diamond qv=q⋄q.

Then vvv is outside the six named points, v≠pv\ne pv=p, v≠uv\ne uv=u, and p=u⋄vp=u\diamond vp=u⋄v. Moreover, the full five-way one-step classification admits the following refinement, preserving each original packet and branch payload. If both p,up,up,u lie on CtC_tCt​, either vvv occupies a third distinct phase there with the oriented phase-product identity, or vvv starts a disjoint cycle. If ppp starts a new cycle and uuu lies on CtC_tCt​ or CpC_pCp​, then vvv lies on CtC_tCt​, lies on CpC_pCp​, or starts a cycle disjoint from both. Every contact keeps the identity p=u⋄vp=u\diamond vp=u⋄v in its corresponding ordered phase form; phases on CpC_pCp​ are strictly positive, and same-cycle phases of u,vu,vu,v are distinct. The two branches in which uuu escapes retain their original full payloads.

The conclusion supplies both the q-square seed facts and this complete refined outcome. It does not establish recursive renewal or a fixer at xxx.

Preamble
import Definitions.Def_FiniteMagmaE677_sswap_renewal
import Mathlib

universe u
open FiniteMagmaE677
Formal statement
theorem FiniteMagmaE677.period_four_swapped_s_q_square_refinement
{α : Type u} [Fintype α] (op : α → α → α) (h : FiniteMagmaE677.E677 op)
(x c1 c2 c3 q s t : α)
(first : FirstReturn.D4FirstReturn op x c1 c2 c3 t 0)
(pump : SSwap.Pump op x c1 c2 c3 q s t
  (op q (op q x)) (op q (op q (op q x))) first) :
SSwap.QSquareSeed op x c1 c2 c3 q s (op q (op q x)) (op q (op q (op q x))) ∧
SSwap.QSquareOutcome op x c1 c2 c3 q s t
  (op q (op q x)) (op q (op q (op q x))) first := by sorry
Source
Adam McKenna, The Missing Pair (private repository), revision f9945b937be61f4ca48eb6cafdcfa07ba7a7f78c, lean/E677/Spine/Piece1D4SSwapQSquareRenewal.lean, line 35, and lean/E677/Spine/Piece1D4SSwapPNewQSquareRenewal.lean, line 377. The accepted proof on this platform is the public record.

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