Thomson $N=7$, slab 2: minimal pair with $t_{01}\in[-\tfrac{49}{50},-\tfrac{24}{25}]$ gives $E>E(P)$

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Thomson $N=7$, slab 2: minimal pair with $t_{01}\in[-\tfrac{49}{50},-\tfrac{24}{25}]$ gives $E>E(P)$ · Prove2Me