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Proposition 2.1 — consumer's best response â(z), b̂(γ) and the closed forms of H_m, H_v (H_m corrected beyond A_max)

Proved
DemandResponse.FirstBest.prop2_1_best_response

by mikedeng1 · Oct 4, 2026 · Mathlib 0df444a (Lean v4.33.1)

demand-responsep2o-batch-pfp1ap2o-gran-per-chapterp2o-plan-paperp2o-v1principal-agentstochastic-control

In the demand-response model, let A=∏i[0,μiAmax⁡]A=\prod_i[0,\mu_iA_{\max}]A=∏i​[0,μi​Amax​], B=[ε,1]dB=[\varepsilon,1]^dB=[ε,1]d, c1(a)=12∑iai2/μic_1(a)=\frac12\sum_ia_i^2/\mu_ic1​(a)=21​∑i​ai2​/μi​, c2(b)=∑jσj2λj(bj−1−1)c_2(b)=\sum_j\frac{\sigma_j^2}{\lambda_j}(b_j^{-1}-1)c2​(b)=∑j​λj​σj2​​(bj−1​−1) and ∣σ(b)∣2=∑jσj2bj|\sigma(b)|^2=\sum_j\sigma_j^2b_j∣σ(b)∣2=∑j​σj2​bj​, and let HmH_mHm​, HvH_vHv​ be the Hamiltonians (2.9). Let a^i(z)=μi(z−∧Amax⁡)\hat a_i(z)=\mu_i(z^-\wedge A_{\max})a^i​(z)=μi​(z−∧Amax​) and b^j(γ)=(1∧(λjγ−)−1/2)∨ε\hat b_j(\gamma)=(1\wedge(\lambda_j\gamma^-)^{-1/2})\vee\varepsilonb^j​(γ)=(1∧(λj​γ−)−1/2)∨ε for j=1,…,dj=1,\dots,dj=1,…,d. Then:

  1. for every z∈Rz\in\mathbb Rz∈R, a^(z)∈A\hat a(z)\in Aa^(z)∈A and a^(z)\hat a(z)a^(z) minimises a↦a⋅1 z+c1(a)a\mapsto a\cdot\mathbf 1\,z+c_1(a)a↦a⋅1z+c1​(a) over AAA;
  2. for every γ∈R\gamma\in\mathbb Rγ∈R, b^(γ)∈B\hat b(\gamma)\in Bb^(γ)∈B and b^(γ)\hat b(\gamma)b^(γ) minimises b↦c2(b)−γ∣σ(b)∣2b\mapsto c_2(b)-\gamma|\sigma(b)|^2b↦c2​(b)−γ∣σ(b)∣2 over BBB;
  3. for every zzz, with m:=z−∧Amax⁡m:=z^-\wedge A_{\max}m:=z−∧Amax​,
Hm(z)=μˉ(m z−−m22);H_m(z)=\bar\mu\Big(m\,z^--\frac{m^2}2\Big);Hm​(z)=μˉ​(mz−−2m2​);
  1. for every γ\gammaγ, Hv(γ)=−12(c2(b^(γ))−γ∣σ(b^(γ))∣2)H_v(\gamma)=-\frac12\big(c_2(\hat b(\gamma))-\gamma|\sigma(\hat b(\gamma))|^2\big)Hv​(γ)=−21​(c2​(b^(γ))−γ∣σ(b^(γ))∣2).

The Hamiltonian is the consumer's instantaneous benefit from a payment rate zzz on the consumption drift and γ\gammaγ on its volatility; this proposition makes it explicit, and it is what turns the first-best value into a closed form.

Formalization Note The paper prints Hm(z)=12μˉ(z−∧Amax⁡)2H_m(z)=\frac12\bar\mu(z^-\wedge A_{\max})^2Hm​(z)=21​μˉ​(z−∧Amax​)2, which is false when z−>Amax⁡z^->A_{\max}z−>Amax​ (for N=1N=1N=1, μ=1\mu=1μ=1, Amax⁡=1A_{\max}=1Amax​=1, z=−10z=-10z=−10 the minimum of −10a+a2/2-10a+a^2/2−10a+a2/2 over [0,1][0,1][0,1] is −9.5-9.5−9.5, so Hm=9.5H_m=9.5Hm​=9.5, not 0.50.50.5). Item 3 is the corrected formula, equal to the printed one exactly when z−≤Amax⁡z^-\le A_{\max}z−≤Amax​. The page's index range "j=1,…,Nj=1,\dots,Nj=1,…,N" for b^\hat bb^ is read as j=1,…,dj=1,\dots,dj=1,…,d. When γ−=0\gamma^-=0γ−=0 the paper reads (λjγ−)−1/2(\lambda_j\gamma^-)^{-1/2}(λj​γ−)−1/2 as +∞+\infty+∞, so b^j=1\hat b_j=1b^j​=1; the Lean definition makes this case explicit.

Preamble
import Mathlib
import Definitions.Def_DemandResponse_FirstBest_Hamiltonian
Formal statement
namespace DemandResponse.FirstBest

/-- Proposition 2.1 (consumer's best response), with the closed form of `H_m` corrected beyond
`Amax` and the index range of `b̂` read as `j = 1, …, d`. -/
theorem prop2_1_best_response {N d : ℕ} (P : Params N d) :
    (∀ z : ℝ, aHat P z ∈ effortA P ∧ ∀ a ∈ effortA P,
      (∑ i, aHat P z i) * z + c1 P (aHat P z) ≤ (∑ i, a i) * z + c1 P a) ∧
    (∀ γ : ℝ, bHat P γ ∈ effortB P ∧ ∀ b ∈ effortB P,
      c2 P (bHat P γ) - γ * sigSq P (bHat P γ) ≤ c2 P b - γ * sigSq P b) ∧
    (∀ z : ℝ, Hm P z =
      muBar P * (min (xneg z) P.Amax * xneg z - min (xneg z) P.Amax ^ 2 / 2)) ∧
    (∀ γ : ℝ, Hv P γ = -(1 / 2) * (c2 P (bHat P γ) - γ * sigSq P (bHat P γ))) := by sorry

end DemandResponse.FirstBest
Source
arXiv:1810.09063v3, Proposition 2.1 (p. 9)
Human review
  • Endorsed by Shuze Chen · Oct 4, 2026

    Confirmed by the moderator at approval.

  • Endorsed by mikedeng1 · Oct 4, 2026

    Confirmed by the mission captain (proposal self-audit).

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