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Irregularity of {a,b,d,e} in a quintuple

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diophantine_quintuple_abde_irregular

by xuanji · Sep 7, 2026 · Mathlib 0df444a (Lean v4.33.1)

diophantine-equationsnumber-theory

Let a<b<c<d<ea<b<c<d<ea<b<c<d<e be a Diophantine quintuple, and choose natural-number witnesses

r2=ab+1,s2=ad+1,t2=bd+1.r^2=ab+1,\qquad s^2=ad+1,\qquad t^2=bd+1.r2=ab+1,s2=ad+1,t2=bd+1.

Then

eea+b+d+2abd+2rst.e e a+b+d+2abd+2rst.eea+b+d+2abd+2rst.

In other words, the quadruple formed by the first, second, fourth, and fifth entries is irregular. This is the explicit irregularity assertion used in the source's proof of the quintuple range bound to apply the extension criterion contrapositively. It is stated as a separate obligation because that proof asserts irregularity without a derivation at that point.

Preamble
import Definitions.Def_diophantine_descent
set_option autoImplicit false
open DiophantineDescent
Formal statement
theorem diophantine_quintuple_abde_irregular (f : Fin 5 → Nat)
    (hq : Quintuple f) (ho : Ordered f) (r s t : Nat)
    (hr : f 0 * f 1 + 1 = r ^ 2) (hs : f 0 * f 3 + 1 = s ^ 2)
    (ht : f 1 * f 3 + 1 = t ^ 2) :
    f 4 ≠ f 0 + f 1 + f 3 + 2 * f 0 * f 1 * f 3 + 2 * r * s * t := by sorry
Source
Bo He, Alain Togbe, Volker Ziegler, arXiv:1610.04020v2, proof of Lemma lem:acb: `By Fujita's result (Theorem thm:fujita), the Diophantine quadruple {a,b,c,d} is regular. Consider the irregular Diophantine quadruple {a,b,d,e}.' No lemma number or justification is given for the irregularity; it is isolated here as an explicit child rather than silently assumed. Source text: https://arxiv.org/abs/1610.04020v2.

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