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Two maps on 232^323 points with no common hole on any 3-set (Erdős 624)

Proved
Erdos624.pair_common_hole_false_k3

by Ethan Cheung Wang · Oct 23, 2026 · Mathlib 0df444a (Lean v4.33.1)

combinatoricserdos-problems

Theorem. Let ∣U∣=8=23|U|=8=2^3∣U∣=8=23. There are two maps g0,g1:P(U)→Ug_0,g_1:\mathcal P(U)\to Ug0​,g1​:P(U)→U such that for every 333-set Y⊆UY\subseteq UY⊆U and every u∈Uu\in Uu∈U, some gig_igi​ takes the value uuu on a subset of YYY.

So the two-map common-hole statement ('for ∣U∣=2k|U|=2^k∣U∣=2k, any two maps miss a common point on some kkk-set'), which would give one unit of gain over the counting bound for Erdős Problem 624, is false at k=3k=3k=3; e.g. gi(A)=(i,min⁡(∣A∣,3))g_i(A)=(i,\min(|A|,3))gi​(A)=(i,min(∣A∣,3)) on U={0,1}×{0,1,2,3}U=\{0,1\}\times\{0,1,2,3\}U={0,1}×{0,1,2,3}. Each map misses half of UUU on every 3-set, yet the missed sets are disjoint. The statement for large kkk remains open.

Formalization Note. U=Fin (23)U=\mathrm{Fin}\,(2^3)U=Fin(23), maps indexed by Fin 2\mathrm{Fin}\,2Fin2; special case r=2,n=8,k=3r=2,n=8,k=3r=2,n=8,k=3 of rank_cover.

Preamble
import Mathlib
import Definitions.Def_Erdos624_defs
open Finset
Formal statement
namespace Erdos624

theorem pair_common_hole_false_k3:
    ¬ ∀ g : Fin 2 → Finset (Fin (2 ^ 3)) → Fin (2 ^ 3),
      ∃ Y : Finset (Fin (2 ^ 3)), #Y = 3 ∧ ∃ u, ∀ i, ∀ A ⊆ Y, g i A ≠ u := by sorry

end Erdos624
Source
Erdős Problem 624 (https://www.erdosproblems.com/624); definitions from Formal Conjectures 624.lean; (B2) of claim from GPT 6.1 Sol (fourth answer, Oct 23 2026), Lean-verified by Grok Bot for Ethan Cheung (Oct 23 2026)

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