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Trivial common hole for several maps P(U)→U\mathcal P(U)\to UP(U)→U (Erdős 624)

Proved
Erdos624.commonHole

by Ethan Cheung Wang · Oct 23, 2026 · Mathlib 0df444a (Lean v4.33.1)

combinatoricserdos-problems

Theorem. Let UUU and III be finite sets, let gi:P(U)→Ug_i:\mathcal P(U)\to Ugi​:P(U)→U for i∈Ii\in Ii∈I, and let Y⊆UY\subseteq UY⊆U. If ∣I∣⋅2∣Y∣<∣U∣|I|\cdot 2^{|Y|}<|U|∣I∣⋅2∣Y∣<∣U∣, then some u∈Uu\in Uu∈U is omitted by every gig_igi​ on the subsets of YYY:

u∉⋃i∈I{gi(A):A⊆Y}.u\notin\bigcup_{i\in I}\{g_i(A):A\subseteq Y\}.u∈/i∈I⋃​{gi​(A):A⊆Y}.

The union has at most ∣I∣ 2∣Y∣|I|\,2^{|Y|}∣I∣2∣Y∣ elements. This is the counting-range common-hole lemma for Erdős Problem 624; it only works where ∣Y∣+log⁡2∣I∣<log⁡2∣U∣|Y|+\log_2|I|<\log_2|U|∣Y∣+log2​∣I∣<log2​∣U∣, so it gives no improvement over the counting bound H(n)≥⌈log⁡2n⌉H(n)\ge\lceil\log_2 n\rceilH(n)≥⌈log2​n⌉.

Preamble
import Mathlib
import Definitions.Def_Erdos624_defs
open Finset
Formal statement
namespace Erdos624

theorem commonHole {U ι : Type*} [Fintype U] [DecidableEq U] [Fintype ι]
    (g : ι → Finset U → U) (Y : Finset U) (h : Fintype.card ι * 2 ^ #Y < Fintype.card U) :
    ∃ u, ∀ i, ∀ A ⊆ Y, g i A ≠ u := by sorry

end Erdos624
Source
Erdős Problem 624 (https://www.erdosproblems.com/624); definitions from Formal Conjectures 624.lean; Claim B1 of claim from GPT 6.1 Sol (second answer, Oct 23 2026), Lean-verified by Grok Bot for Ethan Cheung (Oct 23 2026)

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