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Some genuinely quantum boxes are strictly parity-distillable

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QAlgorithms.Papers.Independent.Intakethird100.P48.theorem_2

by Gohan · Nov 1, 2026 · Mathlib 0df444a (Lean v4.33.1)

prove2quantum

For real parameters ε,δ\varepsilon,\deltaε,δ, define Pε,δP_{\varepsilon,\delta}Pε,δ​ as follows. At a binary input pair xyxyxy, put r=εr=\varepsilonr=ε if xy=11xy=11xy=11, and r=δr=\deltar=δ otherwise. Each equal-output pair has probability (1−r)/2(1-r)/2(1−r)/2 and each unequal-output pair has probability r/2r/2r/2. These tables have uniform marginals. Let NDP⁡n\operatorname{NDP}_nNDPn​ apply the same local input to nnn independent identical resource copies and return separate local XORs; let NL⁡\operatorname{NL}NL be the full absolute CHSH maximum.

There exist parameters and a copy number satisfying

0<δ<ε<12,n>1,0<\delta<\varepsilon<\tfrac12,\qquad n>1,0<δ<ε<21​,n>1,

such that the whole table Pε,δP_{\varepsilon,\delta}Pε,δ​ is quantum-realizable and the local-XOR output is a valid non-signaling behavior with

NL⁡(NDP⁡n(Pε,δ))>NL⁡(Pε,δ)>2.\operatorname{NL}\bigl(\operatorname{NDP}_n(P_{\varepsilon,\delta})\bigr)> \operatorname{NL}(P_{\varepsilon,\delta})>2.NL(NDPn​(Pε,δ​))>NL(Pε,δ​)>2.

Quantum realizability means exact local-measurement probabilities on a normalized bipartite state, including the uniform marginals. This establishes distillation within the quantum set, with existence rather than universality over all quantum boxes.

Preamble
import Definitions.Def_QAlgorithms_Papers_Independent_Intakethird100_P48
Formal statement
namespace QAlgorithms.Papers.Independent.Intakethird100.P48

open scoped BigOperators TensorProduct

noncomputable section

/-- PDF p.3, Theorem 2: some 0<delta<epsilon<1/2 quantum resource is strictly
distilled by NDP_n for some n>1. Quantum refers to the entire behavior. -/
theorem theorem_2 :
    ∃ (epsilon delta : ℝ) (n : ℕ),
      0 < delta ∧ delta < epsilon ∧ epsilon < 1 / 2 ∧ 1 < n ∧
      IsQuantum (parameterBox epsilon delta) ∧
      StrictlyDistills (parityProtocol n) (parameterBox epsilon delta) := by sorry

end

end QAlgorithms.Papers.Independent.Intakethird100.P48
Source
Distilling Non-Locality, arXiv:0809.3173v4, PDF p. 3, Theorem 2: a quantum box is strictly distillable
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What the Lean code literally says, in plain math · gpt-6.1-sol

There exist real numbers ϵ,δ\epsilon,\deltaϵ,δ and a natural number nnn satisfying 0<δ<ϵ<1/20<\delta<\epsilon<1/20<δ<ϵ<1/2 and n>1n>1n>1 with the following properties. Identify Boolean values with 0,10,10,1, set r11=ϵr_{11}=\epsilonr11​=ϵ and rxy=δr_{xy}=\deltarxy​=δ at the other input pairs, and define P(x,y,a,b)=(1−rxy)/2P(x,y,a,b)=(1-r_{xy})/2P(x,y,a,b)=(1−rxy​)/2 when a=ba=ba=b, and rxy/2r_{xy}/2rxy​/2 otherwise. There exist complete complex inner-product spaces A,BA,BA,B, a unit vector ψ∈A⊗CB^\psi\in\widehat{A\otimes_{\mathbb C}B}ψ∈A⊗C​B​, and positive continuous complex-linear operators Mx,aM_{x,a}Mx,a​ and Ny,bN_{y,b}Ny,b​, with Mx,0+Mx,1=IAM_{x,0}+M_{x,1}=I_AMx,0​+Mx,1​=IA​ and Ny,0+Ny,1=IBN_{y,0}+N_{y,1}=I_BNy,0​+Ny,1​=IB​, such that P(x,y,a,b)=Re⁡⟨ψ,Mx,a⊗Ny,b^ψ⟩P(x,y,a,b)=\operatorname{Re}\langle\psi,\widehat{M_{x,a}\otimes N_{y,b}}\psi\rangleP(x,y,a,b)=Re⟨ψ,Mx,a​⊗Ny,b​​ψ⟩ for every Boolean quadruple; the hat denotes the induced map on the completion. Define

(TnP)(x,y,a,b)=∑u,v∈{0,1}n⨁iui=a, ⨁ivi=b∏i=0n−1P(x,y,ui,vi),(T_nP)(x,y,a,b)= \sum_{\substack{u,v\in\{0,1\}^n\\ \bigoplus_i u_i=a,\ \bigoplus_i v_i=b}} \prod_{i=0}^{n-1}P(x,y,u_i,v_i),(Tn​P)(x,y,a,b)=u,v∈{0,1}n⨁i​ui​=a, ⨁i​vi​=b​∑​i=0∏n−1​P(x,y,ui​,vi​),

where ⨁\bigoplus⨁ is addition modulo two. Both PPP and TnPT_nPTn​P have nonnegative entries, total mass one at every input pair, first-output marginals independent of the second input, and second-output marginals independent of the first input. With CS(x,y)=S(x,y,0,0)+S(x,y,1,1)−S(x,y,0,1)−S(x,y,1,0)C_S(x,y)=S(x,y,0,0)+S(x,y,1,1)-S(x,y,0,1)-S(x,y,1,0)CS​(x,y)=S(x,y,0,0)+S(x,y,1,1)−S(x,y,0,1)−S(x,y,1,0) and L(S)=max⁡x,y∣CS(x,y)+CS(x,1−y)+CS(1−x,y)−CS(1−x,1−y)∣L(S)=\max_{x,y}|C_S(x,y)+C_S(x,1-y)+C_S(1-x,y)-C_S(1-x,1-y)|L(S)=maxx,y​∣CS​(x,y)+CS​(x,1−y)+CS​(1−x,y)−CS​(1−x,1−y)∣, they satisfy 2<L(P)<L(TnP)2<L(P)<L(T_nP)2<L(P)<L(Tn​P).

Human review
  • Endorsed by Shuze Chen · Nov 1, 2026

    Confirmed by the moderator at approval.

  • Endorsed by Gohan · Nov 1, 2026

    Confirmed by the mission captain (proposal self-audit).

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