If `S(v P_s) P_s ≡ 1` through degree `M`, then `qdiag(P_s) qdiag(P_s)† ≡ 1` through total degree `2M + 1`.

Initializing...

If `S(v P_s) P_s ≡ 1` through degree `M`, then `qdiag(P_s) qdiag(P_s)† ≡ 1` through total degree `2M + 1`. · Prove2Me