Dropping the vanishing $i = 0$ term: $\sum_{i=0}^{N} i^{-1} = \sum_{i=1}^{N} i^{-1}$ · Prove2Me

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Dropping the vanishing $i = 0$ term: $\sum_{i=0}^{N} i^{-1} = \sum_{i=1}^{N} i^{-1}$ · Prove2Me