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Weighted profile value is bounded by the fifth class value

Proved
mme_stothers_phi116_profile_value_le_class_value

by WillR · Sep 5, 2026 · Mathlib 777aaa6 (Lean v4.29.0-rc3)

algebraic-complexitydavie-stothersinequalityphi-116tau-value

For the positive Davie--Stothers parameters L(6,τ)L(6,\tau)L(6,τ) and E(6,τ)E(6,\tau)E(6,τ) and any 0<a<10<a<10<a<1, the optimized two-component profile value satisfies

4(2L(6,τ)a)a(E(6,τ)21−a)1−a≤4(E(6,τ)2+2L(6,τ)).4\left(\frac{2L(6,\tau)}{a}\right)^a\left(\frac{E(6,\tau)^2}{1-a}\right)^{1-a}\le 4\bigl(E(6,\tau)^2+2L(6,\tau)\bigr).4(a2L(6,τ)​)a(1−aE(6,τ)2​)1−a≤4(E(6,τ)2+2L(6,τ)).

The right-hand side is the fifth class value in the source table. The inequality is the weighted arithmetic--geometric mean inequality and supplies the numerical bridge from the arbitrary profile parameter in the phi-116 frontier theorem to its class-value interface.

Preamble
import Mathlib.Analysis.MeanInequalities
import Mathlib.Tactic
import Definitions.Def_mme_stothers_fourth_data

open MME
universe u
Formal statement
theorem mme_stothers_phi116_profile_value_le_class_value
    (tau a : Real) (haPos : 0 < a) (haLt : a < 1) :
    4 * (((2 * MME.StothersFourth.L 6 tau) / a) ^ a *
      ((MME.StothersFourth.E 6 tau ^ (2 : ℕ)) / (1 - a)) ^ (1 - a)) ≤
      MME.StothersFourth.classValue 6 tau 5 := by
  sorry
Source
A. M. Davie and A. J. Stothers, Improved Bound for Complexity of Matrix Multiplication (2013), Section 5, Lemma 5.1 and the fifth class-value entry; https://www.maths.ed.ac.uk/~sandy/a11164.pdf.

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