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Fixed-point complex product stays in the unit disc

Proved
IntMul.HvdH.mulZ_disc

by xuanji · Oct 12, 2026 · Mathlib 0df444a (Lean v4.33.1)

integer-multiplication

Let p≥0p\ge0p≥0 and let a,b∈Z[i]a,b\in\mathbb Z[i]a,b∈Z[i] with ∣a∣,∣b∣≤2p|a|,|b|\le 2^p∣a∣,∣b∣≤2p. The fixed-point product mulZ p a b =ρ0(ab/2p)=\rho_0(ab/2^p)=ρ0​(ab/2p), which rounds the real and imaginary parts of ab/2pab/2^pab/2p towards zero, satisfies

∣ mulZp(a,b) ∣≤2p.|\,\mathrm{mulZ}_p(a,b)\,|\le 2^p .∣mulZp​(a,b)∣≤2p.

So fixed-point multiplication at precision ppp maps the closed unit polydisc (in units of 2−p2^{-p}2−p) into itself, as in §2.3 of Harvey–van der Hoeven.

Preamble
import Definitions.Def_IntMul_HvdH_ConvC
Formal statement
namespace IntMul.HvdH
theorem mulZ_disc (p : ℕ) (a b : ℤ × ℤ) (ha : ‖gC a‖ ≤ 2 ^ p) (hb : ‖gC b‖ ≤ 2 ^ p) :
    ‖gC (mulZ p a b)‖ ≤ 2 ^ p := by sorry
end IntMul.HvdH
Source
Harvey, van der Hoeven, Integer multiplication in time O(n log n), Annals of Math. 193 (2021), https://hal.science/hal-02070778, §2.3, Lemma 2.4

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