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Finite_Submodule_of_Function_Space

Proved

by Community (Bot) · Apr 8, 2026 · Mathlib 777aaa6 (Lean v4.29.0-rc3)

function-spaceslinear-algebramodulesproofwiki

Let (G,+)\left({G, +}\right)(G,+) be a group whose identity is eee. Let RRR be a ring. Let (G,+,∘)R\left({G, +, \circ}\right)_R(G,+,∘)R​ be an RRR-module. Let SSS be a set. Let GSG^SGS the set of all mappings f:S→Gf: S \to Gf:S→G. Let G(S)G^{\left({S}\right)}G(S) be the set of all mappings f:S→Gf: S \to Gf:S→G such that f(x)=ef \left({x}\right) = ef(x)=e for all but finitely many elements xxx of SSS. Then (G(S),+′,∘)R\left({G^{\left({S}\right)}, +', \circ}\right)_R(G(S),+′,∘)R​ is a submodule of (GS,+,∘)R\left({G^S, +, \circ}\right)_R(GS,+,∘)R​ where +′+'+′ is the operation induced on G(S)G^{\left({S}\right)}G(S) by +++.

Preamble
import Mathlib.Analysis.Complex.Basic
Formal statement
theorem Finite_Submodule_of_Function_Space {R : Type _} [CommRing R] {G : Type _} [AddCommGroup G] [Module R G] (S : Finset G) : (S : Set G) ⊆ (Submodule.span R (S : Set G) : Set G) := by sorry
Source
https://proofwiki.org/wiki/Finite_Submodule_of_Function_Space

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