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Coarse orientation of a Hlawka counterexample for p≥32p\ge 32p≥32

Proved
HlawkaSchatten.DiagonalCutoff32.coarse32

by @bwdaugherty · Oct 16, 2026 · Mathlib 0df444a (Lean v4.33.1)

functional-analysis

Let 32≤p≤5032\le p\le 5032≤p≤50 with 0.448 p<Kp0.448\,p<K_p0.448p<Kp​, and let 0<q≤0.3860<q\le 0.3860<q≤0.386 with scalarEnvelope(p,q)<Kp\mathrm{scalarEnvelope}(p,q)<K_pscalarEnvelope(p,q)<Kp​. If three real vectors x,y,z∈R3x,y,z\in\mathbb R^3x,y,z∈R3 violate Hlawka's inequality with constant KpK_pKp​ for the ℓp\ell_pℓp​ norm, then there is a 3×33\times 33×3 real matrix XXX with rows X0,X1,X2X_0,X_1,X_2X0​,X1​,X2​ such that

  1. entries in the coarse box: D=[−1.158,−0.555]D=[-1.158,-0.555]D=[−1.158,−0.555] for diagonal entries and O=[0.79,1.158]O=[0.79,1.158]O=[0.79,1.158] for off-diagonal entries;
  2. ∥X0∥p+∥X1∥p+∥X2∥p=3\|X_0\|_p+\|X_1\|_p+\|X_2\|_p=3∥X0​∥p​+∥X1​∥p​+∥X2​∥p​=3 and ∥X0+X1+X2∥p<3q\|X_0+X_1+X_2\|_p<3q∥X0​+X1​+X2​∥p​<3q;
  3. pair-gap sum below 2/(0.448 p)2/(0.448\,p)2/(0.448p);
  4. the triple deficit of XXX at KpK_pKp​ is negative.

Here violating Hlawka's inequality with constant KKK means (2K−1)(∥x∥p+∥y∥p+∥z∥p)+∥x+y+z∥p<K(∥x+y∥p+∥x+z∥p+∥y+z∥p)(2K-1)(\|x\|_p+\|y\|_p+\|z\|_p)+\|x+y+z\|_p<K(\|x+y\|_p+\|x+z\|_p+\|y+z\|_p)(2K−1)(∥x∥p​+∥y∥p​+∥z∥p​)+∥x+y+z∥p​<K(∥x+y∥p​+∥x+z∥p​+∥y+z∥p​).

It is the entrance step of the localization of a counterexample.

Preamble
import Definitions.Def_HlawkaSchatten_DiagonalConstruction_Cyclic
import Definitions.Def_HlawkaSchatten_DiagonalConstruction_ScalarBounds
import Definitions.Def_HlawkaSchatten_DiagonalConstruction_Localization
import Definitions.Def_HlawkaSchatten_GapComparison
import Mathlib

open HlawkaSchatten HlawkaSchatten.DiagonalConstruction
Formal statement
theorem HlawkaSchatten.DiagonalCutoff32.coarse32 : ∀ p : ℝ, 32 ≤ p → p ≤ 50 →
    (448 / 1000 : ℝ) * p < cyclicConstant p →
    ∀ q : ℝ, 0 < q → q ≤ 386 / 1000 → scalarEnvelope p q < cyclicConstant p →
    ∀ x y z : Fin 3 → ℝ, hlawkaDeficit p (cyclicConstant p) x y z < 0 →
      ∃ X : Triple,
        (∀ j i, if j = i then -(1158 / 1000 : ℝ) ≤ X j i ∧ X j i ≤ -(555 / 1000 : ℝ)
                 else (79 / 100 : ℝ) ≤ X j i ∧ X j i ≤ (1158 / 1000 : ℝ)) ∧
        lpNorm p (X 0) + lpNorm p (X 1) + lpNorm p (X 2) = 3 ∧
        lpNorm p (X 0 + X 1 + X 2) < 3 * q ∧
        pairGapSum (lpNorm p) (X 0) (X 1) (X 2) < 2 / ((448 / 1000) * p) ∧
        tripleDeficit p (cyclicConstant p) X < 0 := by sorry
Source
Sharp diagonal Hlawka constant campaign, cutoff-32 entry (https://prove2.me/campaigns/sharp-diagonal-hlawka-constant); definitions of the foundation mission (Ezzeri Esa, Apache-2.0).

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