Coarse orientation of a Hlawka counterexample for
ProvedHlawkaSchatten.DiagonalCutoff32.coarse32functional-analysis
Let with , and let with . If three real vectors violate Hlawka's inequality with constant for the norm, then there is a real matrix with rows such that
- entries in the coarse box: for diagonal entries and for off-diagonal entries;
- and ;
- pair-gap sum below ;
- the triple deficit of at is negative.
Here violating Hlawka's inequality with constant means .
It is the entrance step of the localization of a counterexample.
Preamble
import Definitions.Def_HlawkaSchatten_DiagonalConstruction_Cyclic import Definitions.Def_HlawkaSchatten_DiagonalConstruction_ScalarBounds import Definitions.Def_HlawkaSchatten_DiagonalConstruction_Localization import Definitions.Def_HlawkaSchatten_GapComparison import Mathlib open HlawkaSchatten HlawkaSchatten.DiagonalConstruction
Formal statement
theorem HlawkaSchatten.DiagonalCutoff32.coarse32 : ∀ p : ℝ, 32 ≤ p → p ≤ 50 →
(448 / 1000 : ℝ) * p < cyclicConstant p →
∀ q : ℝ, 0 < q → q ≤ 386 / 1000 → scalarEnvelope p q < cyclicConstant p →
∀ x y z : Fin 3 → ℝ, hlawkaDeficit p (cyclicConstant p) x y z < 0 →
∃ X : Triple,
(∀ j i, if j = i then -(1158 / 1000 : ℝ) ≤ X j i ∧ X j i ≤ -(555 / 1000 : ℝ)
else (79 / 100 : ℝ) ≤ X j i ∧ X j i ≤ (1158 / 1000 : ℝ)) ∧
lpNorm p (X 0) + lpNorm p (X 1) + lpNorm p (X 2) = 3 ∧
lpNorm p (X 0 + X 1 + X 2) < 3 * q ∧
pairGapSum (lpNorm p) (X 0) (X 1) (X 2) < 2 / ((448 / 1000) * p) ∧
tripleDeficit p (cyclicConstant p) X < 0 := by sorrySource
Sharp diagonal Hlawka constant campaign, cutoff-32 entry (https://prove2.me/campaigns/sharp-diagonal-hlawka-constant); definitions of the foundation mission (Ezzeri Esa, Apache-2.0).