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Matching-covered board boundary cancellation

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MagicSquares.matching_boundary_euler

by Yuxuan Xu · Sep 22, 2026 · Mathlib 0df444a (Lean v4.33.1)

combinatoricsmagic-squaresmobius-inversion

Let n≥1n\ge 1n≥1 and let a board be a subset of [n]×[n][n]\times[n][n]×[n]. For a permutation σ\sigmaσ, write ϕσ={(i,σ(i)):i∈[n]}\phi_\sigma=\{(i,\sigma(i)):i\in[n]\}ϕσ​={(i,σ(i)):i∈[n]}. A board is matching-covered if it is nonempty and each of its cells belongs to some permutation support contained in the board. Define

a(C)=∑S⊆C(−1)∣S∣1{C∖S contains a permutation support}.a(C)=\sum_{S\subseteq C}(-1)^{|S|}\mathbf 1\{C\setminus S\text{ contains a permutation support}\}.a(C)=S⊆C∑​(−1)∣S∣1{C∖S contains a permutation support}.

For any matching-covered boards D⊆BD\subseteq BD⊆B and any permutation support ϕσ⊆B\phi_\sigma\subseteq Bϕσ​⊆B, the following finite boundary identity holds:

∑D⊆C⊆BB∖ϕσ⊆Ca(C)={a(B),ϕσ⊆D,0,ϕσ⊈D.\sum_{\substack{D\subseteq C\subseteq B\\B\setminus\phi_\sigma\subseteq C}}a(C)=\begin{cases}a(B),&\phi_\sigma\subseteq D,\\0,&\phi_\sigma\nsubseteq D.\end{cases}D⊆C⊆BB∖ϕσ​⊆C​∑​a(C)={a(B),0,​ϕσ​⊆D,ϕσ​⊈D.​

The summation includes all such boards CCC, without requiring them to be matching-covered. This identity provides a finite combinatorial sufficient condition for reciprocity of semi-magic counting polynomials. Its formal proof is the remaining obligation in the associated conditional reduction.

Preamble
import Mathlib
import Definitions.Def_MagicSquaresMatchingBoundary
Formal statement
namespace MagicSquares

theorem matching_boundary_euler (n : ℕ) (hn : 1 ≤ n) :
    MagicSquaresBoundary.MatchingBoundaryCriterion n := by
  sorry

end MagicSquares
Source
Original matching-board specialization of the Eulerian face-lattice property and the order-dual of Weisner's theorem; derived in MATCHING-BOUNDARY-SOURCE.md. Richard P. Stanley, Enumerative Combinatorics, Volume 1, author manuscript, Proposition 3.8.9, p. 309, and Corollary 3.9.3, p. 313: https://math.mit.edu/~rstan/ec/ec1.pdf. This matching-board statement is our specialization, not a verbatim theorem in that source.

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