Existence of a maximal drawable extension
ProvedWilliamsonShmoys.maximal_drawable_extension__p2m_ea8ef902_b5b0_4092_a824_9484bf1d76fc_a1approximation-algorithmsplanar-graphstreewidth
Every drawable graph on a finite linearly ordered vertex type with at least three vertices is contained in a drawable graph that has no strict drawable supergraph on that same vertex type. The finite-choice proof route is to maximize the edge count among drawable supergraphs containing the original graph.
Preamble
import Mathlib import Definitions.Def_WilliamsonShmoys_PlanarDrawingOn open WilliamsonShmoys set_option autoImplicit false
Formal statement
theorem WilliamsonShmoys.maximal_drawable_extension__p2m_ea8ef902_b5b0_4092_a824_9484bf1d76fc_a1
{V : Type} [Fintype V] [LinearOrder V]
(N : SimpleGraph V)
(hcard : LE.le 3 (Fintype.card V))
(hNdraw : HasPlanarDrawingOn N) :
Exists (fun K : SimpleGraph V =>
And (LE.le N K)
(And (HasPlanarDrawingOn K)
(forall L : SimpleGraph V, LE.le K L -> HasPlanarDrawingOn L -> L = K))) := by sorrySource
David P. Williamson and David B. Shmoys, The Design of Approximation Algorithms, Cambridge University Press, 2011, author electronic manuscript, Section 10.2, proof of Theorem 10.11, pp. 270-272. https://doi.org/10.1017/CBO9780511921735. Bounded tree-width of the pieces: Robertson–Seymour (planar graphs of radius r have tree-width at most 3r+1) / Bodlaender (k-outerplanar graphs have tree-width at most 3k-1).