Read-back: FiniteEnergyPlane.isFastPlane_iff_hasWindInfAt_one
Setting. Here V=R4 with coordinates (v0,v1,v2,v3), and
j0(v)=(−v1,v0,−v3,v2),ω0(u,v)=⟨j0u,v⟩=u0v1−u1v0+u2v3−u3v2,λx(v)=21ω0(x,v).
The gradient of H is taken coordinatewise, XH(x)=j0(∇H(x)), and the Reeb field is R(x)=λx(XH(x))−1XH(x). If λx(XH(x))=0, the inverse is 0 by convention, so R(x)=0. The energy surface is S={H=1}. The condition "v∈ξx" means λx(v)=0 and dHx(v)=0.
- Strictly star-shaped H: H is C∞; for every u=0 there is exactly one r>0 with H(ru)=1; and dHx(x)>0 whenever H(x)=1.
- Compatible ξ-structure J:R4→L(R4,R4): J is C∞, and for every x∈S and v,w∈ξx we have Jxv∈ξx, JxJxv=−v, ω0(v,Jxv)>0 if v=0, and ω0(Jxv,Jxw)=ω0(v,w). Nothing is required of Jx off ξx or for x∈/S.
- Reeb orbit P=(x,T): a map x:R→R4 and a number T>0 with x(τ)∈S, x′(τ)=R(x(τ)) and x(τ+T)=x(τ) for all τ. The period T need not be minimal. P is called prime if x(τ)=x(0) for all 0<τ<T.
- Rescaling: σ(y) is a chosen r>0 with H(ry)=1 if one exists, and σ(y)=1 otherwise. For y=0 this r is unique; for y=0 with H(0)=1 it is an arbitrary positive choice. Then proj(y)=σ(y)y and a(y)=−21logσ(y).
- Extended structure J~: put x=proj(y), r=σ(y), α(v)=rdHx(v)/(2dHx(x)), β(v)=rλx(v) and w(v)=v−α(v)2y−β(v)r−1R(x). Then
J~(y)v=α(v)r−1R(x)−β(v)2y+Jx(w(v)).
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Finite-energy curve on C: a map u:C→R4 such that
- u is C∞ on C and u(z)=0 for every z;
- at every z, u is differentiable and ∂su+J~(u)∂tu=0, where ∂s and ∂t are the derivatives in the directions 1 and i;
- E(u)<∞.
Here, with au=a∘u and wu=proj∘u,
E(u)=φsup∫Cmax(0, φ′(au)(∂sauλwu(∂twu)−∂tauλwu(∂swu))+φ(au)ω0(∂swu,∂twu))dz.
The supremum runs over C∞ monotone φ:R→[0,1], and the integral is a lower Lebesgue integral with values in [0,∞].
- "Nondegenerate end" at ∞ asymptotic to P with ε=1: let e(s,t)=e2πse2πit and W(s,t)=proj(u(e(s,t))). There are d,c,b∈R with b>0 such that, uniformly in t∈R as s→+∞,
a(u(e(s,t)))−Ts−d→0andebs(W(s,t)−x(Tt+c))→0.
This condition is only exponential uniform convergence of the end. It says nothing about the linearized return map of P.
- Loop winding: a function f:R→C has loop winding k∈Z if
- f is continuous, 1-periodic and never zero;
- there is a continuous θ:R→R with f(t)=∣f(t)∣eiθ(t) for all t;
- θ(1)−θ(0)=2πk.
- ξ-coordinates: ξC(x,v)=ω0(v,f2(x))+iω0(f1(x),v)∈C, with frames
f1(x)=∣x∣−1(Q2x−dHx(x)dHx(Q2x)x),f2(x)=∣x∣−1(Q1x−dHx(x)dHx(Q1x)x),
where Q1x=(−x2,x3,x0,−x1) and Q2x=(x3,x2,−x1,−x0). Division by 0 gives 0. The Reeb-removing map is πξ(x,v)=v−λx(v)R(x).
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Winding k at ∞: there is s0 such that, for every s≥s0, the loop t↦ξC(W(s,t), πξ(W(s,t),∂sW(s,t))) has loop winding k. Here ∂sW is the Fréchet derivative of W on R2 applied to (1,0), which is 0 by convention wherever W is not differentiable.
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π-winding k (with no punctures): let wu=proj∘u and D(z)=ξC(wu(z), πξ(wu(z),∂swu(z))). The condition says the zero set of D on C is a finite set Z, and there are integers idx(z), for z∈Z, with ∑z∈Zidx(z)=k. Each zero z0∈Z must have local index idx(z0), meaning:
- there is r>0 such that z0 is the only zero of D in the closed disc Bˉ(z0,r);
- for every ρ∈(0,r), the loop t↦D(z0+ρe2πit) has loop winding idx(z0).
When k=0, Z need not be empty: only the sum of the indices is 0.
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Fast plane u: u is a finite-energy curve on C; there is some prime Reeb orbit P′ such that u has a nondegenerate end at ∞ asymptotic to P′ with ε=1 (in the sense above); and u has π-winding 0 with no punctures.
Statement. Let:
- H:R4→R be strictly star-shaped;
- J be a compatible ξ-structure for H;
- u:C→R4 be a finite-energy curve on C;
- P=(x,T) be a prime Reeb orbit of H such that u has a nondegenerate end at ∞ asymptotic to P with ε=1.
Then the following two conditions are equivalent:
- u is a fast plane. By the definition above, this means u is a finite-energy curve, some prime Reeb orbit P′ (not necessarily P) is asymptotic to u at ∞ in the above sense, and u has π-winding 0 with no punctures.
- u has winding exactly 1 at ∞: for all sufficiently large s, the loop t↦ξC(W(s,t),πξ(W(s,t),∂sW(s,t))) has loop winding 1.
Under the hypotheses, the first two parts of the fast-plane condition already hold (take P′=P). So condition 1 amounts to the π-winding-0 condition.
Confirmed by the moderator at approval.