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Prop. 4.0.1 — in metric spaces, sequential completeness implies completeness for nets

Proved
GarrettFA.metric_net_complete_of_seq_complete

by Lucas · Oct 12, 2026 · Mathlib 0df444a (Lean v4.33.1)

functional-analysistopological-vector-spaces

Let (M,d)(M,d)(M,d) be a metric space in which every Cauchy sequence converges. Let (vi)i∈I(v_i)_{i\in I}(vi​)i∈I​ be a net indexed by a directed partially ordered set that is Cauchy for ddd: for every ε>0\varepsilon>0ε>0 there is i0i_0i0​ with d(vi,vj)<εd(v_i,v_j)<\varepsilond(vi​,vj​)<ε for all i,j≥i0i,j\ge i_0i,j≥i0​. Then there is x∈Mx\in Mx∈M such that

  1. the net converges to xxx: for every ε>0\varepsilon>0ε>0 there is i0i_0i0​ with d(vi,x)<εd(v_i,x)<\varepsilond(vi​,x)<ε for all i≥i0i\ge i_0i≥i0​; and
  2. there is a monotone sequence of indices i1≤i2≤⋯i_1\le i_2\le\cdotsi1​≤i2​≤⋯ with vin→xv_{i_n}\to xvin​​→x.

Formalization Note The notes speak of "cofinal sequences converging to the same limit". A directed set need not contain a cofinal sequence, so this clause is formalized as a monotone sequence of indices along which the net converges to xxx, which is what the proof constructs.

Preamble
import Mathlib
Formal statement
namespace GarrettFA
theorem metric_net_complete_of_seq_complete {M : Type*} [MetricSpace M]
    (hM : ∀ u : ℕ → M, CauchySeq u → ∃ x, Filter.Tendsto u Filter.atTop (nhds x))
    {I : Type*} [PartialOrder I] [IsDirected I (· ≤ ·)] (v : I → M)
    (hv : ∀ ε > 0, ∃ i₀ : I, ∀ i ≥ i₀, ∀ j ≥ i₀, dist (v i) (v j) < ε) :
    ∃ x : M, (∀ ε > 0, ∃ i₀ : I, ∀ i ≥ i₀, dist (v i) x < ε) ∧
      ∃ s : ℕ → I, Monotone s ∧ Filter.Tendsto (v ∘ s) Filter.atTop (nhds x) := by sorry
end GarrettFA
Source
Paul Garrett, *Completeness and quasi-completeness* (lecture notes, April 24, 2014), http://www.math.umn.edu/~garrett/m/fun/notes_2012-13/07d_quasi-completeness.pdf, p. 6, Proposition 4.0.1
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What the Lean code literally says, in plain math · Aristotle (Harmonic)

Let MMM be a metric space with distance ddd (no vector structure). Assume MMM is sequentially complete: every Cauchy sequence (un)n∈N(u_n)_{n\in\mathbb N}(un​)n∈N​ in MMM converges to some point of MMM. Let III be any type (any universe) with a partial order in which any two elements have a common upper bound, and let v:I→Mv:I\to Mv:I→M satisfy the Cauchy condition: for every ε>0\varepsilon>0ε>0 there is i0i_0i0​ with d(vi,vj)<εd(v_i,v_j)<\varepsilond(vi​,vj​)<ε for all i,j≥i0i,j\ge i_0i,j≥i0​. Then there exists x∈Mx\in Mx∈M such that both

  1. for every ε>0\varepsilon>0ε>0 there is i0i_0i0​ with d(vi,x)<εd(v_i,x)<\varepsilond(vi​,x)<ε for all i≥i0i\ge i_0i≥i0​ (the net converges to xxx), and
  2. there is a monotone sequence of indices s:N→Is:\mathbb N\to Is:N→I (n≤m⇒sn≤smn\le m\Rightarrow s_n\le s_mn≤m⇒sn​≤sm​) such that vsn→xv_{s_n}\to xvsn​​→x as n→∞n\to\inftyn→∞.

The sequence sss is only required to be monotone; it is not required to be cofinal in III. If III is empty the Cauchy hypothesis fails, so the statement is vacuous there.

Human review
  • Endorsed by Shuze Chen · Oct 13, 2026

    Confirmed by the moderator at approval.

  • Endorsed by Lucas · Oct 13, 2026

    Confirmed by the mission captain (proposal self-audit).

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