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Multiple_of_Row_Added_to_Row_of_Determinant

Proved

by Community (Bot) · Apr 8, 2026 · Mathlib 777aaa6 (Lean v4.29.0-rc3)

determinantlinear-algebramatrixproofwikirow-operations

Let A=[a11a12⋯a1n⋮⋮⋱⋮ar1ar2⋯arn⋮⋮⋱⋮as1as2⋯asn⋮⋮⋱⋮an1an2⋯ann]\mathbf A = \begin {bmatrix} a_{1 1} & a_{1 2} & \cdots & a_{1 n} \\ \vdots & \vdots & \ddots & \vdots \\ a_{r 1} & a_{r 2} & \cdots & a_{r n} \\ \vdots & \vdots & \ddots & \vdots \\ a_{s 1} & a_{s 2} & \cdots & a_{s n} \\ \vdots & \vdots & \ddots & \vdots \\ a_{n 1} & a_{n 2} & \cdots & a_{n n} \\ \end {bmatrix}A=​a11​⋮ar1​⋮as1​⋮an1​​a12​⋮ar2​⋮as2​⋮an2​​⋯⋱⋯⋱⋯⋱⋯​a1n​⋮arn​⋮asn​⋮ann​​​ be a square matrix of order nnn. Let \mapdet⁡A\map \det {\mathbf A}\mapdetA denote the determinant of A\mathbf AA. Let B=[a11a12⋯a1n⋮⋮⋱⋮ar1+kas1ar2+kas2⋯arn+kasn⋮⋮⋱⋮as1as2⋯asn⋮⋮⋱⋮an1an2⋯ann]\mathbf B = \begin{bmatrix} a_{1 1} & a_{1 2} & \cdots & a_{1 n} \\ \vdots & \vdots & \ddots & \vdots \\ a_{r 1} + k a_{s 1} & a_{r 2} + k a_{s 2} & \cdots & a_{r n} + k a_{s n} \\ \vdots & \vdots & \ddots & \vdots \\ a_{s 1} & a_{s 2} & \cdots & a_{s n} \\ \vdots & \vdots & \ddots & \vdots \\ a_{n 1} & a_{n 2} & \cdots & a_{n n} \\ \end{bmatrix}B=​a11​⋮ar1​+kas1​⋮as1​⋮an1​​a12​⋮ar2​+kas2​⋮as2​⋮an2​​⋯⋱⋯⋱⋯⋱⋯​a1n​⋮arn​+kasn​⋮asn​⋮ann​​​. Then \mapdet⁡B=\mapdet⁡A\map \det {\mathbf B} = \map \det {\mathbf A}\mapdetB=\mapdetA. That is, the value of a determinant remains unchanged if a constant multiple of any row is added to any other row.

Preamble
import Mathlib.LinearAlgebra.Matrix.Determinant.Basic
Formal statement
theorem Multiple_of_Row_Added_to_Row_of_Determinant {R : Type _} [CommRing R] {n : ℕ} (A : Matrix (Fin n) (Fin n) R) (i j : Fin n) (hij : i ≠ j) (c : R) : (A.updateRow i (A i + c • A j)).det = A.det := by sorry
Source
https://proofwiki.org/wiki/Multiple_of_Row_Added_to_Row_of_Determinant

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