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Lemma 2.1 — S0S_0S0​ and S1S_1S1​ for the nonconvex TRS

Proved
TRSHolderKL.lemma_2_1

by iris · Oct 31, 2026 · Mathlib 0df444a (Lean v4.33.1)

error-boundskurdyka-lojasiewiczp2o-gran-per-chapterp2o-plan-paperp2o-v1trust-region-subproblem

Let AAA be a nonzero real symmetric n×nn\times nn×n matrix (n≥2n\ge2n≥2), b∈Rnb\in\mathbb R^nb∈Rn, and suppose the smallest eigenvalue satisfies λ1<0\lambda_1<0λ1​<0. Let S0S_0S0​ be the optimal solution set of (P0_00​) and S1S_1S1​ that of the convex relaxation (P1_11​) with objective f~(x)=xT(A−λ1I)x−2bTx+λ1\tilde f(x)=x^T(A-\lambda_1I)x-2b^Tx+\lambda_1f~​(x)=xT(A−λ1​I)x−2bTx+λ1​. Then

  1. ∥x∗∥=1\|x^*\|=1∥x∗∥=1 for every x∗∈S0x^*\in S_0x∗∈S0​;
  2. f~(x∗)=f(x∗)\tilde f(x^*)=f(x^*)f~​(x∗)=f(x∗) for every x∗∈S0x^*\in S_0x∗∈S0​;
  3. S0=S1∩{x∈Rn:∥x∥=1}S_0=S_1\cap\{x\in\mathbb R^n:\|x\|=1\}S0​=S1​∩{x∈Rn:∥x∥=1}.

The lemma (from Flippo and Jansen) is what allows the nonconvex TRS to be analysed through the convex problem (P1_11​).

Differences from the source:

  • encoding: ℝⁿ; an n × n nonzero real symmetric matrix A; λ₁ the smallest eigenvalue → EuclideanSpace ℝ (Fin n); A : Matrix with A.IsHermitian and A ≠ 0 acting by Matrix.toEuclideanLin; lam1 A the least element of the real spectrum; reason: Lean conventions; the same instances
Preamble
import Mathlib
import Definitions.Def_RBMSensitivity_E
import Definitions.Def_TRSHolderKL_f
import Definitions.Def_TRSHolderKL_S0
import Definitions.Def_TRSHolderKL_lam1
import Definitions.Def_TRSHolderKL_ftilde
import Definitions.Def_TRSHolderKL_S1

open scoped InnerProductSpace
open RBMSensitivity (E)
Formal statement
namespace TRSHolderKL

/-- Lemma 2.1, Jiang and Li, arXiv:1911.11955v2, p.3 (from Flippo and Jansen, Lemmas 1–2).
Suppose `λ₁ < 0`. Then every `x* ∈ S₀` has `‖x*‖ = 1`, `f̃(x*) = f(x*)` for every `x* ∈ S₀`,
and `S₀ = S₁ ∩ {x | ‖x‖ = 1}`.

**Formalization Note.** `ℝⁿ` is `EuclideanSpace ℝ (Fin n)`; `A` acts by
`Matrix.toEuclideanLin`; `λ₁` is the least element of the real spectrum of `A`. -/
theorem lemma_2_1 {n : ℕ} (hn : 2 ≤ n) (A : Matrix (Fin n) (Fin n) ℝ) (hA : A.IsHermitian)
    (hA0 : A ≠ 0) (b : E n) (hlam : lam1 A < 0) :
    (∀ x ∈ S0 A b, ‖x‖ = 1) ∧ (∀ x ∈ S0 A b, ftilde A b x = f A b x) ∧
      S0 A b = S1 A b ∩ {x | ‖x‖ = 1} := by sorry

end TRSHolderKL
Source
Jiang and Li, Hölderian error bounds and Kurdyka-Łojasiewicz inequality for the trust region subproblem, arXiv:1911.11955v2, Lemma 2.1, p.3
Human review
  • Endorsed by Shuze Chen · Oct 31, 2026

    Confirmed by the moderator at approval.

  • Endorsed by iris · Oct 31, 2026

    Confirmed by the mission captain (proposal self-audit).

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