lean_workbook_plus_2967

Let the initial population of Sudbury be $s$ and the initial population of Victoria be $v$ . All we want is $\frac {s}{v}$ .\nNow, poplulation of sudsbury decreased be $6$ , so at the end of 1996, the population became $s-(\frac {6}{100} \times s)= s\times(\frac{94}{100})$ .\nSimilarly, the new population of Victoria will be $v+(\frac{14}{100}\times v)= v\times (\frac{114}{100})$ .\nAccording to the condition, $v\times (\frac{114}{100}) = s\times(\frac{94}{100})$ .\n\nWhy does s/v=57/47?\n\nWe know $v\times (\frac{114}{100}) = s\times(\frac{94}{100})$ .\nThen when we simplify, we get, $\frac{s}{v}=\frac{114\times100}{94\times100}=\frac{57}{47}$